| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.54 |
| Score | 0% | 71% |
A tiger in a zoo has consumed 120 pounds of food in 8 days. If the tiger continues to eat at the same rate, in how many more days will its total food consumtion be 180 pounds?
| 4 | |
| 10 | |
| 9 | |
| 8 |
If the tiger has consumed 120 pounds of food in 8 days that's \( \frac{120}{8} \) = 15 pounds of food per day. The tiger needs to consume 180 - 120 = 60 more pounds of food to reach 180 pounds total. At 15 pounds of food per day that's \( \frac{60}{15} \) = 4 more days.
Which of the following is not an integer?
1 |
|
\({1 \over 2}\) |
|
-1 |
|
0 |
An integer is any whole number, including zero. An integer can be either positive or negative. Examples include -77, -1, 0, 55, 119.
A bread recipe calls for 3\(\frac{5}{8}\) cups of flour. If you only have \(\frac{3}{8}\) cup, how much more flour is needed?
| 2\(\frac{3}{8}\) cups | |
| 2\(\frac{1}{8}\) cups | |
| 3\(\frac{1}{4}\) cups | |
| 2 cups |
The amount of flour you need is (3\(\frac{5}{8}\) - \(\frac{3}{8}\)) cups. Rewrite the quantities so they share a common denominator and subtract:
(\( \frac{29}{8} \) - \( \frac{3}{8} \)) cups
\( \frac{26}{8} \) cups
3\(\frac{1}{4}\) cups
What is the least common multiple of 9 and 15?
| 12 | |
| 67 | |
| 98 | |
| 45 |
The first few multiples of 9 are [9, 18, 27, 36, 45, 54, 63, 72, 81, 90] and the first few multiples of 15 are [15, 30, 45, 60, 75, 90]. The first few multiples they share are [45, 90] making 45 the smallest multiple 9 and 15 have in common.
4! = ?
5 x 4 x 3 x 2 x 1 |
|
3 x 2 x 1 |
|
4 x 3 x 2 x 1 |
|
4 x 3 |
A factorial has the form n! and is the product of the integer (n) and all the positive integers below it. For example, 5! = 5 x 4 x 3 x 2 x 1 = 120.