ASVAB Arithmetic Reasoning Practice Test 629290 Results

Your Results Global Average
Questions 5 5
Correct 0 2.85
Score 0% 57%

Review

1

Simplify \( \sqrt{28} \)

62% Answer Correctly
2\( \sqrt{7} \)
6\( \sqrt{14} \)
7\( \sqrt{7} \)
5\( \sqrt{14} \)

Solution

To simplify a radical, factor out the perfect squares:

\( \sqrt{28} \)
\( \sqrt{4 \times 7} \)
\( \sqrt{2^2 \times 7} \)
2\( \sqrt{7} \)


2

Solve 2 + (4 + 2) ÷ 2 x 2 - 32

52% Answer Correctly
1
2\(\frac{1}{2}\)
-1
1\(\frac{2}{5}\)

Solution

Use PEMDAS (Parentheses, Exponents, Multipy/Divide, Add/Subtract):

2 + (4 + 2) ÷ 2 x 2 - 32
P: 2 + (6) ÷ 2 x 2 - 32
E: 2 + 6 ÷ 2 x 2 - 9
MD: 2 + \( \frac{6}{2} \) x 2 - 9
MD: 2 + \( \frac{12}{2} \) - 9
AS: \( \frac{4}{2} \) + \( \frac{12}{2} \) - 9
AS: \( \frac{16}{2} \) - 9
AS: \( \frac{16 - 18}{2} \)
\( \frac{-2}{2} \)
-1


3

Which of these numbers is a factor of 20?

68% Answer Correctly
20
17
2
7

Solution

The factors of a number are all positive integers that divide evenly into the number. The factors of 20 are 1, 2, 4, 5, 10, 20.


4

What is \( \frac{2}{2} \) - \( \frac{4}{6} \)?

61% Answer Correctly
2 \( \frac{3}{6} \)
\( \frac{4}{6} \)
\(\frac{1}{3}\)
1 \( \frac{5}{8} \)

Solution

To subtract these fractions, first find the lowest common multiple of their denominators. The first few multiples of 2 are [2, 4, 6, 8, 10, 12, 14, 16, 18, 20] and the first few multiples of 6 are [6, 12, 18, 24, 30, 36, 42, 48, 54, 60]. The first few multiples they share are [6, 12, 18, 24, 30] making 6 the smallest multiple 2 and 6 share.

Next, convert the fractions so each denominator equals the lowest common multiple:

\( \frac{2 x 3}{2 x 3} \) - \( \frac{4 x 1}{6 x 1} \)

\( \frac{6}{6} \) - \( \frac{4}{6} \)

Now, because the fractions share a common denominator, you can subtract them:

\( \frac{6 - 4}{6} \) = \( \frac{2}{6} \) = \(\frac{1}{3}\)


5

What is 4\( \sqrt{6} \) x 5\( \sqrt{3} \)?

41% Answer Correctly
20\( \sqrt{9} \)
20\( \sqrt{6} \)
60\( \sqrt{2} \)
20\( \sqrt{3} \)

Solution

To multiply terms with radicals, multiply the coefficients and radicands separately:

4\( \sqrt{6} \) x 5\( \sqrt{3} \)
(4 x 5)\( \sqrt{6 \times 3} \)
20\( \sqrt{18} \)

Now we need to simplify the radical:

20\( \sqrt{18} \)
20\( \sqrt{2 \times 9} \)
20\( \sqrt{2 \times 3^2} \)
(20)(3)\( \sqrt{2} \)
60\( \sqrt{2} \)