| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.38 |
| Score | 0% | 68% |
Convert b-4 to remove the negative exponent.
| \( \frac{1}{b^{-4}} \) | |
| \( \frac{-1}{-4b^{4}} \) | |
| \( \frac{-1}{b^{-4}} \) | |
| \( \frac{1}{b^4} \) |
To convert a negative exponent to a positive exponent, calculate the positive exponent then take the reciprocal.
A bread recipe calls for 2\(\frac{5}{8}\) cups of flour. If you only have 1\(\frac{3}{8}\) cups, how much more flour is needed?
| 2\(\frac{5}{8}\) cups | |
| 1\(\frac{1}{2}\) cups | |
| 1\(\frac{5}{8}\) cups | |
| 1\(\frac{1}{4}\) cups |
The amount of flour you need is (2\(\frac{5}{8}\) - 1\(\frac{3}{8}\)) cups. Rewrite the quantities so they share a common denominator and subtract:
(\( \frac{21}{8} \) - \( \frac{11}{8} \)) cups
\( \frac{10}{8} \) cups
1\(\frac{1}{4}\) cups
If all of a roofing company's 6 workers are required to staff 2 roofing crews, how many workers need to be added during the busy season in order to send 5 complete crews out on jobs?
| 6 | |
| 17 | |
| 9 | |
| 2 |
In order to find how many additional workers are needed to staff the extra crews you first need to calculate how many workers are on a crew. There are 6 workers at the company now and that's enough to staff 2 crews so there are \( \frac{6}{2} \) = 3 workers on a crew. 5 crews are needed for the busy season which, at 3 workers per crew, means that the roofing company will need 5 x 3 = 15 total workers to staff the crews during the busy season. The company already employs 6 workers so they need to add 15 - 6 = 9 new staff for the busy season.
Simplify \( \sqrt{48} \)
| 7\( \sqrt{6} \) | |
| 4\( \sqrt{3} \) | |
| 7\( \sqrt{3} \) | |
| 5\( \sqrt{3} \) |
To simplify a radical, factor out the perfect squares:
\( \sqrt{48} \)
\( \sqrt{16 \times 3} \)
\( \sqrt{4^2 \times 3} \)
4\( \sqrt{3} \)
What is the next number in this sequence: 1, 6, 11, 16, 21, __________ ?
| 29 | |
| 25 | |
| 26 | |
| 18 |
The equation for this sequence is:
an = an-1 + 5
where n is the term's order in the sequence, an is the value of the term, and an-1 is the value of the term before an. This makes the next number:
a6 = a5 + 5
a6 = 21 + 5
a6 = 26