The factors of 60 are [1, 2, 3, 4, 5, 6, 10, 12, 15, 20, 30, 60] and the factors of 52 are [1, 2, 4, 13, 26, 52]. They share 3 factors [1, 2, 4] making 4 the greatest factor 60 and 52 have in common.

If the tiger has consumed 143 pounds of food in 11 days that's \( \frac{143}{11} \) = 13 pounds of food per day. The tiger needs to consume 182 - 143 = 39 more pounds of food to reach 182 pounds total. At 13 pounds of food per day that's \( \frac{39}{13} \) = 3 more days.

To divide terms with exponents, the base of both exponents must be the same. In this case they are so divide the coefficients and subtract the exponents:

\( \frac{b^6}{6b^2} \)
\( \frac{1}{6} \) b^{(6 - 2)}
\(\frac{1}{6}\)b⁴

To multiply terms with radicals, multiply the coefficients and radicands separately:

5\( \sqrt{6} \) x 4\( \sqrt{4} \)
(5 x 4)\( \sqrt{6 \times 4} \)
20\( \sqrt{24} \)

Now we need to simplify the radical:

20\( \sqrt{24} \)
20\( \sqrt{6 \times 4} \)
20\( \sqrt{6 \times 2^2} \)
(20)(2)\( \sqrt{6} \)
40\( \sqrt{6} \)

To multiply fractions, multiply the numerators together and then multiply the denominators together:

\( \frac{1}{5} \) x \( \frac{3}{5} \) = \( \frac{1 x 3}{5 x 5} \) = \( \frac{3}{25} \) = \(\frac{3}{25}\)