| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.45 |
| Score | 0% | 69% |
What is \( \frac{3}{6} \) x \( \frac{1}{8} \)?
| \(\frac{1}{16}\) | |
| \(\frac{2}{9}\) | |
| \(\frac{1}{10}\) | |
| \(\frac{12}{25}\) |
To multiply fractions, multiply the numerators together and then multiply the denominators together:
\( \frac{3}{6} \) x \( \frac{1}{8} \) = \( \frac{3 x 1}{6 x 8} \) = \( \frac{3}{48} \) = \(\frac{1}{16}\)
Convert a-2 to remove the negative exponent.
| \( \frac{2}{a} \) | |
| \( \frac{-2}{a} \) | |
| \( \frac{-1}{-2a^{2}} \) | |
| \( \frac{1}{a^2} \) |
To convert a negative exponent to a positive exponent, calculate the positive exponent then take the reciprocal.
What is \( \frac{9}{6} \) - \( \frac{7}{14} \)?
| 1 \( \frac{7}{42} \) | |
| 1 | |
| \( \frac{2}{42} \) | |
| 2 \( \frac{9}{15} \) |
To subtract these fractions, first find the lowest common multiple of their denominators. The first few multiples of 6 are [6, 12, 18, 24, 30, 36, 42, 48, 54, 60] and the first few multiples of 14 are [14, 28, 42, 56, 70, 84, 98]. The first few multiples they share are [42, 84] making 42 the smallest multiple 6 and 14 share.
Next, convert the fractions so each denominator equals the lowest common multiple:
\( \frac{9 x 7}{6 x 7} \) - \( \frac{7 x 3}{14 x 3} \)
\( \frac{63}{42} \) - \( \frac{21}{42} \)
Now, because the fractions share a common denominator, you can subtract them:
\( \frac{63 - 21}{42} \) = \( \frac{42}{42} \) = 1
4! = ?
4 x 3 |
|
5 x 4 x 3 x 2 x 1 |
|
3 x 2 x 1 |
|
4 x 3 x 2 x 1 |
A factorial has the form n! and is the product of the integer (n) and all the positive integers below it. For example, 5! = 5 x 4 x 3 x 2 x 1 = 120.
If there were a total of 100 raffle tickets sold and you bought 4 tickets, what's the probability that you'll win the raffle?
| 3% | |
| 4% | |
| 5% | |
| 11% |
You have 4 out of the total of 100 raffle tickets sold so you have a (\( \frac{4}{100} \)) x 100 = \( \frac{4 \times 100}{100} \) = \( \frac{400}{100} \) = 4% chance to win the raffle.