| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.00 |
| Score | 0% | 60% |
What is 6\( \sqrt{4} \) x 6\( \sqrt{3} \)?
| 72\( \sqrt{3} \) | |
| 36\( \sqrt{7} \) | |
| 36\( \sqrt{3} \) | |
| 12\( \sqrt{4} \) |
To multiply terms with radicals, multiply the coefficients and radicands separately:
6\( \sqrt{4} \) x 6\( \sqrt{3} \)
(6 x 6)\( \sqrt{4 \times 3} \)
36\( \sqrt{12} \)
Now we need to simplify the radical:
36\( \sqrt{12} \)
36\( \sqrt{3 \times 4} \)
36\( \sqrt{3 \times 2^2} \)
(36)(2)\( \sqrt{3} \)
72\( \sqrt{3} \)
A factor is a positive __________ that divides evenly into a given number.
mixed number |
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integer |
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fraction |
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improper fraction |
A factor is a positive integer that divides evenly into a given number. For example, the factors of 8 are 1, 2, 4, and 8.
A tiger in a zoo has consumed 108 pounds of food in 9 days. If the tiger continues to eat at the same rate, in how many more days will its total food consumtion be 156 pounds?
| 1 | |
| 4 | |
| 6 | |
| 8 |
If the tiger has consumed 108 pounds of food in 9 days that's \( \frac{108}{9} \) = 12 pounds of food per day. The tiger needs to consume 156 - 108 = 48 more pounds of food to reach 156 pounds total. At 12 pounds of food per day that's \( \frac{48}{12} \) = 4 more days.
\({b + c \over a} = {b \over a} + {c \over a}\) defines which of the following?
commutative property for multiplication |
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commutative property for division |
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distributive property for multiplication |
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distributive property for division |
The distributive property for division helps in solving expressions like \({b + c \over a}\). It specifies that the result of dividing a fraction with multiple terms in the numerator and one term in the denominator can be obtained by dividing each term individually and then totaling the results: \({b + c \over a} = {b \over a} + {c \over a}\). For example, \({a^3 + 6a^2 \over a^2} = {a^3 \over a^2} + {6a^2 \over a^2} = a + 6\).
Solve for \( \frac{4!}{6!} \)
| 504 | |
| 30 | |
| 72 | |
| \( \frac{1}{30} \) |
A factorial is the product of an integer and all the positive integers below it. To solve a fraction featuring factorials, expand the factorials and cancel out like numbers:
\( \frac{4!}{6!} \)
\( \frac{4 \times 3 \times 2 \times 1}{6 \times 5 \times 4 \times 3 \times 2 \times 1} \)
\( \frac{1}{6 \times 5} \)
\( \frac{1}{30} \)