ASVAB Arithmetic Reasoning Practice Test 635121 Results

Your Results Global Average
Questions 5 5
Correct 0 3.00
Score 0% 60%

Review

1

What is 6\( \sqrt{4} \) x 6\( \sqrt{3} \)?

41% Answer Correctly
72\( \sqrt{3} \)
36\( \sqrt{7} \)
36\( \sqrt{3} \)
12\( \sqrt{4} \)

Solution

To multiply terms with radicals, multiply the coefficients and radicands separately:

6\( \sqrt{4} \) x 6\( \sqrt{3} \)
(6 x 6)\( \sqrt{4 \times 3} \)
36\( \sqrt{12} \)

Now we need to simplify the radical:

36\( \sqrt{12} \)
36\( \sqrt{3 \times 4} \)
36\( \sqrt{3 \times 2^2} \)
(36)(2)\( \sqrt{3} \)
72\( \sqrt{3} \)


2

A factor is a positive __________ that divides evenly into a given number.

78% Answer Correctly

mixed number

integer

fraction

improper fraction


Solution

A factor is a positive integer that divides evenly into a given number. For example, the factors of 8 are 1, 2, 4, and 8.


3

A tiger in a zoo has consumed 108 pounds of food in 9 days. If the tiger continues to eat at the same rate, in how many more days will its total food consumtion be 156 pounds?

56% Answer Correctly
1
4
6
8

Solution

If the tiger has consumed 108 pounds of food in 9 days that's \( \frac{108}{9} \) = 12 pounds of food per day. The tiger needs to consume 156 - 108 = 48 more pounds of food to reach 156 pounds total. At 12 pounds of food per day that's \( \frac{48}{12} \) = 4 more days.


4

\({b + c \over a} = {b \over a} + {c \over a}\) defines which of the following?

56% Answer Correctly

commutative property for multiplication

commutative property for division

distributive property for multiplication

distributive property for division


Solution

The distributive property for division helps in solving expressions like \({b + c \over a}\). It specifies that the result of dividing a fraction with multiple terms in the numerator and one term in the denominator can be obtained by dividing each term individually and then totaling the results: \({b + c \over a} = {b \over a} + {c \over a}\). For example, \({a^3 + 6a^2 \over a^2} = {a^3 \over a^2} + {6a^2 \over a^2} = a + 6\).


5

Solve for \( \frac{4!}{6!} \)

67% Answer Correctly
504
30
72
\( \frac{1}{30} \)

Solution

A factorial is the product of an integer and all the positive integers below it. To solve a fraction featuring factorials, expand the factorials and cancel out like numbers:

\( \frac{4!}{6!} \)
\( \frac{4 \times 3 \times 2 \times 1}{6 \times 5 \times 4 \times 3 \times 2 \times 1} \)
\( \frac{1}{6 \times 5} \)
\( \frac{1}{30} \)