| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.33 |
| Score | 0% | 67% |
Find the average of the following numbers: 8, 4, 9, 3.
| 7 | |
| 6 | |
| 1 | |
| 8 |
To find the average of these 4 numbers add them together then divide by 4:
\( \frac{8 + 4 + 9 + 3}{4} \) = \( \frac{24}{4} \) = 6
13 members of a bridal party need transported to a wedding reception but there are only 4 3-passenger taxis available to take them. How many will need to find other transportation?
| 1 | |
| 3 | |
| 7 | |
| 2 |
There are 4 3-passenger taxis available so that's 4 x 3 = 12 total seats. There are 13 people needing transportation leaving 13 - 12 = 1 who will have to find other transportation.
If \(\left|a\right| = 7\), which of the following best describes a?
a = -7 |
|
a = 7 or a = -7 |
|
a = 7 |
|
none of these is correct |
The absolute value is the positive magnitude of a particular number or variable and is indicated by two vertical lines: \(\left|-5\right| = 5\). In the case of a variable absolute value (\(\left|a\right| = 5\)) the value of a can be either positive or negative (a = -5 or a = 5).
Solve for \( \frac{3!}{4!} \)
| \( \frac{1}{4} \) | |
| 4 | |
| \( \frac{1}{20} \) | |
| \( \frac{1}{9} \) |
A factorial is the product of an integer and all the positive integers below it. To solve a fraction featuring factorials, expand the factorials and cancel out like numbers:
\( \frac{3!}{4!} \)
\( \frac{3 \times 2 \times 1}{4 \times 3 \times 2 \times 1} \)
\( \frac{1}{4} \)
\( \frac{1}{4} \)
A circular logo is enlarged to fit the lid of a jar. The new diameter is 55% larger than the original. By what percentage has the area of the logo increased?
| 22\(\frac{1}{2}\)% | |
| 32\(\frac{1}{2}\)% | |
| 27\(\frac{1}{2}\)% | |
| 20% |
The area of a circle is given by the formula A = πr2 where r is the radius of the circle. The radius of a circle is its diameter divided by two so A = π(\( \frac{d}{2} \))2. If the diameter of the logo increases by 55% the radius (and, consequently, the total area) increases by \( \frac{55\text{%}}{2} \) = 27\(\frac{1}{2}\)%