ASVAB Arithmetic Reasoning Practice Test 637324 Results

Your Results Global Average
Questions 5 5
Correct 0 3.33
Score 0% 67%

Review

1

Find the average of the following numbers: 8, 4, 9, 3.

74% Answer Correctly
7
6
1
8

Solution

To find the average of these 4 numbers add them together then divide by 4:

\( \frac{8 + 4 + 9 + 3}{4} \) = \( \frac{24}{4} \) = 6


2

13 members of a bridal party need transported to a wedding reception but there are only 4 3-passenger taxis available to take them. How many will need to find other transportation?

75% Answer Correctly
1
3
7
2

Solution

There are 4 3-passenger taxis available so that's 4 x 3 = 12 total seats. There are 13 people needing transportation leaving 13 - 12 = 1 who will have to find other transportation.


3

If \(\left|a\right| = 7\), which of the following best describes a?

67% Answer Correctly

a = -7

a = 7 or a = -7

a = 7

none of these is correct


Solution

The absolute value is the positive magnitude of a particular number or variable and is indicated by two vertical lines: \(\left|-5\right| = 5\). In the case of a variable absolute value (\(\left|a\right| = 5\)) the value of a can be either positive or negative (a = -5 or a = 5).


4

Solve for \( \frac{3!}{4!} \)

66% Answer Correctly
\( \frac{1}{4} \)
4
\( \frac{1}{20} \)
\( \frac{1}{9} \)

Solution

A factorial is the product of an integer and all the positive integers below it. To solve a fraction featuring factorials, expand the factorials and cancel out like numbers:

\( \frac{3!}{4!} \)
\( \frac{3 \times 2 \times 1}{4 \times 3 \times 2 \times 1} \)
\( \frac{1}{4} \)
\( \frac{1}{4} \)


5

A circular logo is enlarged to fit the lid of a jar. The new diameter is 55% larger than the original. By what percentage has the area of the logo increased?

50% Answer Correctly
22\(\frac{1}{2}\)%
32\(\frac{1}{2}\)%
27\(\frac{1}{2}\)%
20%

Solution

The area of a circle is given by the formula A = πr2 where r is the radius of the circle. The radius of a circle is its diameter divided by two so A = π(\( \frac{d}{2} \))2. If the diameter of the logo increases by 55% the radius (and, consequently, the total area) increases by \( \frac{55\text{%}}{2} \) = 27\(\frac{1}{2}\)%