ASVAB Arithmetic Reasoning Practice Test 639154 Results

Your Results Global Average
Questions 5 5
Correct 0 3.22
Score 0% 64%

Review

1

If a rectangle is twice as long as it is wide and has a perimeter of 12 meters, what is the area of the rectangle?

47% Answer Correctly
8 m2
72 m2
162 m2
50 m2

Solution

The area of a rectangle is width (w) x height (h). In this problem we know that the rectangle is twice as long as it is wide so h = 2w. The perimeter of a rectangle is 2w + 2h and we know that the perimeter of this rectangle is 12 meters so the equation becomes: 2w + 2h = 12.

Putting these two equations together and solving for width (w):

2w + 2h = 12
w + h = \( \frac{12}{2} \)
w + h = 6
w = 6 - h

From the question we know that h = 2w so substituting 2w for h gives us:

w = 6 - 2w
3w = 6
w = \( \frac{6}{3} \)
w = 2

Since h = 2w that makes h = (2 x 2) = 4 and the area = h x w = 2 x 4 = 8 m2


2

This property states taht the order of addition or multiplication does not mater. For example, 2 + 5 and 5 + 2 are equivalent.

60% Answer Correctly

commutative

PEDMAS

associative

distributive


Solution

The commutative property states that, when adding or multiplying numbers, the order in which they're added or multiplied does not matter. For example, 3 + 4 and 4 + 3 give the same result, as do 3 x 4 and 4 x 3.


3

How many 14-passenger vans will it take to drive all 57 members of the football team to an away game?

81% Answer Correctly
7 vans
5 vans
4 vans
6 vans

Solution

Calculate the number of vans needed by dividing the number of people that need transported by the capacity of one van:

vans = \( \frac{57}{14} \) = 4\(\frac{1}{14}\)

So, it will take 4 full vans and one partially full van to transport the entire team making a total of 5 vans.


4

Solve for \( \frac{6!}{2!} \)

67% Answer Correctly
\( \frac{1}{6720} \)
\( \frac{1}{20} \)
9
360

Solution

A factorial is the product of an integer and all the positive integers below it. To solve a fraction featuring factorials, expand the factorials and cancel out like numbers:

\( \frac{6!}{2!} \)
\( \frac{6 \times 5 \times 4 \times 3 \times 2 \times 1}{2 \times 1} \)
\( \frac{6 \times 5 \times 4 \times 3}{1} \)
\( 6 \times 5 \times 4 \times 3 \)
360


5

Convert y-5 to remove the negative exponent.

68% Answer Correctly
\( \frac{1}{y^5} \)
\( \frac{5}{y} \)
\( \frac{-1}{-5y} \)
\( \frac{-5}{-y} \)

Solution

To convert a negative exponent to a positive exponent, calculate the positive exponent then take the reciprocal.