ASVAB Arithmetic Reasoning Practice Test 641000 Results

Your Results Global Average
Questions 5 5
Correct 0 3.46
Score 0% 69%

Review

1

Solve for \( \frac{3!}{4!} \)

66% Answer Correctly
504
\( \frac{1}{3024} \)
\( \frac{1}{4} \)
72

Solution

A factorial is the product of an integer and all the positive integers below it. To solve a fraction featuring factorials, expand the factorials and cancel out like numbers:

\( \frac{3!}{4!} \)
\( \frac{3 \times 2 \times 1}{4 \times 3 \times 2 \times 1} \)
\( \frac{1}{4} \)
\( \frac{1}{4} \)


2

Solve 3 + (2 + 4) ÷ 4 x 4 - 32

52% Answer Correctly
1\(\frac{1}{4}\)
1\(\frac{3}{4}\)
1\(\frac{2}{5}\)

Solution

Use PEMDAS (Parentheses, Exponents, Multipy/Divide, Add/Subtract):

3 + (2 + 4) ÷ 4 x 4 - 32
P: 3 + (6) ÷ 4 x 4 - 32
E: 3 + 6 ÷ 4 x 4 - 9
MD: 3 + \( \frac{6}{4} \) x 4 - 9
MD: 3 + \( \frac{24}{4} \) - 9
AS: \( \frac{12}{4} \) + \( \frac{24}{4} \) - 9
AS: \( \frac{36}{4} \) - 9
AS: \( \frac{36 - 36}{4} \)
\( \frac{0}{4} \)


3

Ezra loaned Damon $500 at an annual interest rate of 9%. If no payments are made, what is the interest owed on this loan at the end of the first year?

74% Answer Correctly
$108
$48
$45
$55

Solution

The yearly interest charged on this loan is the annual interest rate multiplied by the amount borrowed:

interest = annual interest rate x loan amount

i = (\( \frac{6}{100} \)) x $500
i = 0.09 x $500
i = $45


4

Which of the following is a mixed number?

82% Answer Correctly

\(1 {2 \over 5} \)

\({7 \over 5} \)

\({5 \over 7} \)

\({a \over 5} \)


Solution

A rational number (or fraction) is represented as a ratio between two integers, a and b, and has the form \({a \over b}\) where a is the numerator and b is the denominator. An improper fraction (\({5 \over 3} \)) has a numerator with a greater absolute value than the denominator and can be converted into a mixed number (\(1 {2 \over 3} \)) which has a whole number part and a fractional part.


5

What is a3 - 6a3?

71% Answer Correctly
7a9
-5a3
5a-3
7a6

Solution

To add or subtract terms with exponents, both the base and the exponent must be the same. In this case they are so subtract the coefficients and retain the base and exponent:

1a3 - 6a3
(1 - 6)a3
-5a3