| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.38 |
| Score | 0% | 68% |
What is \( \frac{4}{6} \) x \( \frac{2}{7} \)?
| \(\frac{4}{21}\) | |
| \(\frac{2}{9}\) | |
| \(\frac{4}{45}\) | |
| 1\(\frac{1}{3}\) |
To multiply fractions, multiply the numerators together and then multiply the denominators together:
\( \frac{4}{6} \) x \( \frac{2}{7} \) = \( \frac{4 x 2}{6 x 7} \) = \( \frac{8}{42} \) = \(\frac{4}{21}\)
Which of the following is an improper fraction?
\({2 \over 5} \) |
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\(1 {2 \over 5} \) |
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\({a \over 5} \) |
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\({7 \over 5} \) |
A rational number (or fraction) is represented as a ratio between two integers, a and b, and has the form \({a \over b}\) where a is the numerator and b is the denominator. An improper fraction (\({5 \over 3} \)) has a numerator with a greater absolute value than the denominator and can be converted into a mixed number (\(1 {2 \over 3} \)) which has a whole number part and a fractional part.
Convert x-4 to remove the negative exponent.
| \( \frac{1}{x^4} \) | |
| \( \frac{-4}{-x} \) | |
| \( \frac{-1}{-4x} \) | |
| \( \frac{-4}{x} \) |
To convert a negative exponent to a positive exponent, calculate the positive exponent then take the reciprocal.
What is \( \frac{14\sqrt{35}}{2\sqrt{7}} \)?
| 7 \( \sqrt{\frac{1}{5}} \) | |
| \(\frac{1}{5}\) \( \sqrt{7} \) | |
| \(\frac{1}{7}\) \( \sqrt{5} \) | |
| 7 \( \sqrt{5} \) |
To divide terms with radicals, divide the coefficients and radicands separately:
\( \frac{14\sqrt{35}}{2\sqrt{7}} \)
\( \frac{14}{2} \) \( \sqrt{\frac{35}{7}} \)
7 \( \sqrt{5} \)
\({b + c \over a} = {b \over a} + {c \over a}\) defines which of the following?
commutative property for division |
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commutative property for multiplication |
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distributive property for division |
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distributive property for multiplication |
The distributive property for division helps in solving expressions like \({b + c \over a}\). It specifies that the result of dividing a fraction with multiple terms in the numerator and one term in the denominator can be obtained by dividing each term individually and then totaling the results: \({b + c \over a} = {b \over a} + {c \over a}\). For example, \({a^3 + 6a^2 \over a^2} = {a^3 \over a^2} + {6a^2 \over a^2} = a + 6\).