ASVAB Arithmetic Reasoning Practice Test 643111 Results

Your Results Global Average
Questions 5 5
Correct 0 3.26
Score 0% 65%

Review

1

What is the distance in miles of a trip that takes 5 hours at an average speed of 65 miles per hour?

86% Answer Correctly
20 miles
325 miles
375 miles
120 miles

Solution

Average speed in miles per hour is the number of miles traveled divided by the number of hours:

speed = \( \frac{\text{distance}}{\text{time}} \)

Solving for distance:

distance = \( \text{speed} \times \text{time} \)
distance = \( 65mph \times 5h \)
325 miles


2

What is the least common multiple of 2 and 4?

72% Answer Correctly
4
1
8
6

Solution

The first few multiples of 2 are [2, 4, 6, 8, 10, 12, 14, 16, 18, 20] and the first few multiples of 4 are [4, 8, 12, 16, 20, 24, 28, 32, 36, 40]. The first few multiples they share are [4, 8, 12, 16, 20] making 4 the smallest multiple 2 and 4 have in common.


3

Betty scored 82% on her final exam. If each question was worth 4 points and there were 240 possible points on the exam, how many questions did Betty answer correctly?

57% Answer Correctly
57
35
47
49

Solution

Betty scored 82% on the test meaning she earned 82% of the possible points on the test. There were 240 possible points on the test so she earned 240 x 0.82 = 196 points. Each question is worth 4 points so she got \( \frac{196}{4} \) = 49 questions right.


4

What is \( \sqrt{\frac{4}{9}} \)?

70% Answer Correctly
\(\frac{2}{5}\)
\(\frac{2}{3}\)
\(\frac{1}{2}\)
1\(\frac{1}{5}\)

Solution

To take the square root of a fraction, break the fraction into two separate roots then calculate the square root of the numerator and denominator separately:

\( \sqrt{\frac{4}{9}} \)
\( \frac{\sqrt{4}}{\sqrt{9}} \)
\( \frac{\sqrt{2^2}}{\sqrt{3^2}} \)
\(\frac{2}{3}\)


5

What is 2\( \sqrt{9} \) x 3\( \sqrt{2} \)?

41% Answer Correctly
18\( \sqrt{2} \)
5\( \sqrt{2} \)
5\( \sqrt{9} \)
5\( \sqrt{18} \)

Solution

To multiply terms with radicals, multiply the coefficients and radicands separately:

2\( \sqrt{9} \) x 3\( \sqrt{2} \)
(2 x 3)\( \sqrt{9 \times 2} \)
6\( \sqrt{18} \)

Now we need to simplify the radical:

6\( \sqrt{18} \)
6\( \sqrt{2 \times 9} \)
6\( \sqrt{2 \times 3^2} \)
(6)(3)\( \sqrt{2} \)
18\( \sqrt{2} \)