ASVAB Arithmetic Reasoning Practice Test 643457 Results

Your Results Global Average
Questions 5 5
Correct 0 3.06
Score 0% 61%

Review

1

What is \( \frac{42\sqrt{12}}{6\sqrt{4}} \)?

71% Answer Correctly
3 \( \sqrt{7} \)
\(\frac{1}{3}\) \( \sqrt{7} \)
\(\frac{1}{7}\) \( \sqrt{\frac{1}{3}} \)
7 \( \sqrt{3} \)

Solution

To divide terms with radicals, divide the coefficients and radicands separately:

\( \frac{42\sqrt{12}}{6\sqrt{4}} \)
\( \frac{42}{6} \) \( \sqrt{\frac{12}{4}} \)
7 \( \sqrt{3} \)


2

What is \( \frac{6}{4} \) + \( \frac{5}{6} \)?

60% Answer Correctly
2\(\frac{1}{3}\)
2 \( \frac{8}{12} \)
\( \frac{5}{10} \)
2 \( \frac{6}{14} \)

Solution

To add these fractions, first find the lowest common multiple of their denominators. The first few multiples of 4 are [4, 8, 12, 16, 20, 24, 28, 32, 36, 40] and the first few multiples of 6 are [6, 12, 18, 24, 30, 36, 42, 48, 54, 60]. The first few multiples they share are [12, 24, 36, 48, 60] making 12 the smallest multiple 4 and 6 share.

Next, convert the fractions so each denominator equals the lowest common multiple:

\( \frac{6 x 3}{4 x 3} \) + \( \frac{5 x 2}{6 x 2} \)

\( \frac{18}{12} \) + \( \frac{10}{12} \)

Now, because the fractions share a common denominator, you can add them:

\( \frac{18 + 10}{12} \) = \( \frac{28}{12} \) = 2\(\frac{1}{3}\)


3

What is \( \frac{3}{9} \) x \( \frac{3}{6} \)?

72% Answer Correctly
\(\frac{1}{6}\)
1
\(\frac{2}{7}\)
1\(\frac{1}{2}\)

Solution

To multiply fractions, multiply the numerators together and then multiply the denominators together:

\( \frac{3}{9} \) x \( \frac{3}{6} \) = \( \frac{3 x 3}{9 x 6} \) = \( \frac{9}{54} \) = \(\frac{1}{6}\)


4

Solve 4 + (2 + 3) ÷ 4 x 5 - 42

53% Answer Correctly
-5\(\frac{3}{4}\)
1\(\frac{2}{3}\)
1\(\frac{1}{2}\)
\(\frac{1}{2}\)

Solution

Use PEMDAS (Parentheses, Exponents, Multipy/Divide, Add/Subtract):

4 + (2 + 3) ÷ 4 x 5 - 42
P: 4 + (5) ÷ 4 x 5 - 42
E: 4 + 5 ÷ 4 x 5 - 16
MD: 4 + \( \frac{5}{4} \) x 5 - 16
MD: 4 + \( \frac{25}{4} \) - 16
AS: \( \frac{16}{4} \) + \( \frac{25}{4} \) - 16
AS: \( \frac{41}{4} \) - 16
AS: \( \frac{41 - 64}{4} \)
\( \frac{-23}{4} \)
-5\(\frac{3}{4}\)


5

If the ratio of home fans to visiting fans in a crowd is 5:1 and all 33,000 seats in a stadium are filled, how many home fans are in attendance?

49% Answer Correctly
26,400
27,500
31,200
27,333

Solution

A ratio of 5:1 means that there are 5 home fans for every one visiting fan. So, of every 6 fans, 5 are home fans and \( \frac{5}{6} \) of every fan in the stadium is a home fan:

33,000 fans x \( \frac{5}{6} \) = \( \frac{165000}{6} \) = 27,500 fans.