| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.17 |
| Score | 0% | 63% |
A tiger in a zoo has consumed 65 pounds of food in 5 days. If the tiger continues to eat at the same rate, in how many more days will its total food consumtion be 130 pounds?
| 4 | |
| 10 | |
| 5 | |
| 6 |
If the tiger has consumed 65 pounds of food in 5 days that's \( \frac{65}{5} \) = 13 pounds of food per day. The tiger needs to consume 130 - 65 = 65 more pounds of food to reach 130 pounds total. At 13 pounds of food per day that's \( \frac{65}{13} \) = 5 more days.
What is the greatest common factor of 20 and 76?
| 9 | |
| 2 | |
| 4 | |
| 5 |
The factors of 20 are [1, 2, 4, 5, 10, 20] and the factors of 76 are [1, 2, 4, 19, 38, 76]. They share 3 factors [1, 2, 4] making 4 the greatest factor 20 and 76 have in common.
If there were a total of 450 raffle tickets sold and you bought 40 tickets, what's the probability that you'll win the raffle?
| 9% | |
| 17% | |
| 18% | |
| 5% |
You have 40 out of the total of 450 raffle tickets sold so you have a (\( \frac{40}{450} \)) x 100 = \( \frac{40 \times 100}{450} \) = \( \frac{4000}{450} \) = 9% chance to win the raffle.
What is \( \frac{-9c^6}{3c^2} \)?
| -\(\frac{1}{3}\)c4 | |
| -3c3 | |
| -3c4 | |
| -3c8 |
To divide terms with exponents, the base of both exponents must be the same. In this case they are so divide the coefficients and subtract the exponents:
\( \frac{-9c^6}{3c^2} \)
\( \frac{-9}{3} \) c(6 - 2)
-3c4
Simplify \( \sqrt{12} \)
| 3\( \sqrt{3} \) | |
| 2\( \sqrt{3} \) | |
| 7\( \sqrt{6} \) | |
| 4\( \sqrt{6} \) |
To simplify a radical, factor out the perfect squares:
\( \sqrt{12} \)
\( \sqrt{4 \times 3} \)
\( \sqrt{2^2 \times 3} \)
2\( \sqrt{3} \)