ASVAB Arithmetic Reasoning Practice Test 647275 Results

Your Results Global Average
Questions 5 5
Correct 0 3.78
Score 0% 76%

Review

1

A tiger in a zoo has consumed 81 pounds of food in 9 days. If the tiger continues to eat at the same rate, in how many more days will its total food consumtion be 135 pounds?

56% Answer Correctly
5
1
6
4

Solution

If the tiger has consumed 81 pounds of food in 9 days that's \( \frac{81}{9} \) = 9 pounds of food per day. The tiger needs to consume 135 - 81 = 54 more pounds of food to reach 135 pounds total. At 9 pounds of food per day that's \( \frac{54}{9} \) = 6 more days.


2

What is \( \frac{2}{6} \) x \( \frac{3}{7} \)?

72% Answer Correctly
\(\frac{6}{7}\)
\(\frac{1}{6}\)
\(\frac{1}{7}\)
\(\frac{3}{64}\)

Solution

To multiply fractions, multiply the numerators together and then multiply the denominators together:

\( \frac{2}{6} \) x \( \frac{3}{7} \) = \( \frac{2 x 3}{6 x 7} \) = \( \frac{6}{42} \) = \(\frac{1}{7}\)


3

What is the next number in this sequence: 1, 6, 11, 16, 21, __________ ?

92% Answer Correctly
29
17
21
26

Solution

The equation for this sequence is:

an = an-1 + 5

where n is the term's order in the sequence, an is the value of the term, and an-1 is the value of the term before an. This makes the next number:

a6 = a5 + 5
a6 = 21 + 5
a6 = 26


4

Which of the following is a mixed number?

82% Answer Correctly

\(1 {2 \over 5} \)

\({7 \over 5} \)

\({a \over 5} \)

\({5 \over 7} \)


Solution

A rational number (or fraction) is represented as a ratio between two integers, a and b, and has the form \({a \over b}\) where a is the numerator and b is the denominator. An improper fraction (\({5 \over 3} \)) has a numerator with a greater absolute value than the denominator and can be converted into a mixed number (\(1 {2 \over 3} \)) which has a whole number part and a fractional part.


5

What is 6b4 x 3b2?

75% Answer Correctly
9b6
18b6
9b2
18b4

Solution

To multiply terms with exponents, the base of both exponents must be the same. In this case they are so multiply the coefficients and add the exponents:

6b4 x 3b2
(6 x 3)b(4 + 2)
18b6