| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.03 |
| Score | 0% | 61% |
Solve 4 + (5 + 2) ÷ 3 x 4 - 32
| 2\(\frac{1}{4}\) | |
| \(\frac{1}{2}\) | |
| 1 | |
| 4\(\frac{1}{3}\) |
Use PEMDAS (Parentheses, Exponents, Multipy/Divide, Add/Subtract):
4 + (5 + 2) ÷ 3 x 4 - 32
P: 4 + (7) ÷ 3 x 4 - 32
E: 4 + 7 ÷ 3 x 4 - 9
MD: 4 + \( \frac{7}{3} \) x 4 - 9
MD: 4 + \( \frac{28}{3} \) - 9
AS: \( \frac{12}{3} \) + \( \frac{28}{3} \) - 9
AS: \( \frac{40}{3} \) - 9
AS: \( \frac{40 - 27}{3} \)
\( \frac{13}{3} \)
4\(\frac{1}{3}\)
Which of the following is not a prime number?
7 |
|
9 |
|
5 |
|
2 |
A prime number is an integer greater than 1 that has no factors other than 1 and itself. Examples of prime numbers include 2, 3, 5, 7, and 11.
A menswear store is having a sale: "Buy one shirt at full price and get another shirt for 5% off." If Roger buys two shirts, each with a regular price of $40, how much will he pay for both shirts?
| $54.00 | |
| $58.00 | |
| $38.00 | |
| $78.00 |
By buying two shirts, Roger will save $40 x \( \frac{5}{100} \) = \( \frac{$40 x 5}{100} \) = \( \frac{$200}{100} \) = $2.00 on the second shirt.
So, his total cost will be
$40.00 + ($40.00 - $2.00)
$40.00 + $38.00
$78.00
What is the least common multiple of 2 and 6?
| 1 | |
| 8 | |
| 6 | |
| 7 |
The first few multiples of 2 are [2, 4, 6, 8, 10, 12, 14, 16, 18, 20] and the first few multiples of 6 are [6, 12, 18, 24, 30, 36, 42, 48, 54, 60]. The first few multiples they share are [6, 12, 18, 24, 30] making 6 the smallest multiple 2 and 6 have in common.
A tiger in a zoo has consumed 60 pounds of food in 10 days. If the tiger continues to eat at the same rate, in how many more days will its total food consumtion be 84 pounds?
| 13 | |
| 4 | |
| 5 | |
| 10 |
If the tiger has consumed 60 pounds of food in 10 days that's \( \frac{60}{10} \) = 6 pounds of food per day. The tiger needs to consume 84 - 60 = 24 more pounds of food to reach 84 pounds total. At 6 pounds of food per day that's \( \frac{24}{6} \) = 4 more days.