| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.39 |
| Score | 0% | 68% |
What is (z4)4?
| 4z4 | |
| z16 | |
| z0 | |
| z8 |
To raise a term with an exponent to another exponent, retain the base and multiply the exponents:
(z4)4Simplify \( \frac{36}{72} \).
| \( \frac{9}{19} \) | |
| \( \frac{1}{2} \) | |
| \( \frac{6}{17} \) | |
| \( \frac{5}{16} \) |
To simplify this fraction, first find the greatest common factor between them. The factors of 36 are [1, 2, 3, 4, 6, 9, 12, 18, 36] and the factors of 72 are [1, 2, 3, 4, 6, 8, 9, 12, 18, 24, 36, 72]. They share 9 factors [1, 2, 3, 4, 6, 9, 12, 18, 36] making 36 their greatest common factor (GCF).
Next, divide both numerator and denominator by the GCF:
\( \frac{36}{72} \) = \( \frac{\frac{36}{36}}{\frac{72}{36}} \) = \( \frac{1}{2} \)
If all of a roofing company's 12 workers are required to staff 4 roofing crews, how many workers need to be added during the busy season in order to send 8 complete crews out on jobs?
| 17 | |
| 10 | |
| 12 | |
| 11 |
In order to find how many additional workers are needed to staff the extra crews you first need to calculate how many workers are on a crew. There are 12 workers at the company now and that's enough to staff 4 crews so there are \( \frac{12}{4} \) = 3 workers on a crew. 8 crews are needed for the busy season which, at 3 workers per crew, means that the roofing company will need 8 x 3 = 24 total workers to staff the crews during the busy season. The company already employs 12 workers so they need to add 24 - 12 = 12 new staff for the busy season.
The __________ is the greatest factor that divides two integers.
greatest common factor |
|
absolute value |
|
greatest common multiple |
|
least common multiple |
The greatest common factor (GCF) is the greatest factor that divides two integers.
What is \( \frac{4}{5} \) - \( \frac{2}{7} \)?
| \(\frac{18}{35}\) | |
| 1 \( \frac{2}{9} \) | |
| \( \frac{5}{35} \) | |
| 1 \( \frac{5}{10} \) |
To subtract these fractions, first find the lowest common multiple of their denominators. The first few multiples of 5 are [5, 10, 15, 20, 25, 30, 35, 40, 45, 50] and the first few multiples of 7 are [7, 14, 21, 28, 35, 42, 49, 56, 63, 70]. The first few multiples they share are [35, 70] making 35 the smallest multiple 5 and 7 share.
Next, convert the fractions so each denominator equals the lowest common multiple:
\( \frac{4 x 7}{5 x 7} \) - \( \frac{2 x 5}{7 x 5} \)
\( \frac{28}{35} \) - \( \frac{10}{35} \)
Now, because the fractions share a common denominator, you can subtract them:
\( \frac{28 - 10}{35} \) = \( \frac{18}{35} \) = \(\frac{18}{35}\)