| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.82 |
| Score | 0% | 56% |
If all of a roofing company's 12 workers are required to staff 4 roofing crews, how many workers need to be added during the busy season in order to send 6 complete crews out on jobs?
| 6 | |
| 12 | |
| 13 | |
| 16 |
In order to find how many additional workers are needed to staff the extra crews you first need to calculate how many workers are on a crew. There are 12 workers at the company now and that's enough to staff 4 crews so there are \( \frac{12}{4} \) = 3 workers on a crew. 6 crews are needed for the busy season which, at 3 workers per crew, means that the roofing company will need 6 x 3 = 18 total workers to staff the crews during the busy season. The company already employs 12 workers so they need to add 18 - 12 = 6 new staff for the busy season.
What is \( \frac{2}{4} \) + \( \frac{4}{12} \)?
| 2 \( \frac{3}{12} \) | |
| 2 \( \frac{6}{12} \) | |
| 1 \( \frac{1}{12} \) | |
| \(\frac{5}{6}\) |
To add these fractions, first find the lowest common multiple of their denominators. The first few multiples of 4 are [4, 8, 12, 16, 20, 24, 28, 32, 36, 40] and the first few multiples of 12 are [12, 24, 36, 48, 60, 72, 84, 96]. The first few multiples they share are [12, 24, 36, 48, 60] making 12 the smallest multiple 4 and 12 share.
Next, convert the fractions so each denominator equals the lowest common multiple:
\( \frac{2 x 3}{4 x 3} \) + \( \frac{4 x 1}{12 x 1} \)
\( \frac{6}{12} \) + \( \frac{4}{12} \)
Now, because the fractions share a common denominator, you can add them:
\( \frac{6 + 4}{12} \) = \( \frac{10}{12} \) = \(\frac{5}{6}\)
The total water usage for a city is 25,000 gallons each day. Of that total, 30% is for personal use and 46% is for industrial use. How many more gallons of water each day is consumed for industrial use over personal use?
| 5,800 | |
| 2,000 | |
| 4,000 | |
| 4,500 |
46% of the water consumption is industrial use and 30% is personal use so (46% - 30%) = 16% more water is used for industrial purposes. 25,000 gallons are consumed daily so industry consumes \( \frac{16}{100} \) x 25,000 gallons = 4,000 gallons.
What is \( \frac{2}{7} \) x \( \frac{3}{5} \)?
| \(\frac{6}{35}\) | |
| \(\frac{3}{56}\) | |
| \(\frac{2}{9}\) | |
| 1\(\frac{1}{5}\) |
To multiply fractions, multiply the numerators together and then multiply the denominators together:
\( \frac{2}{7} \) x \( \frac{3}{5} \) = \( \frac{2 x 3}{7 x 5} \) = \( \frac{6}{35} \) = \(\frac{6}{35}\)
What is \( 4 \)\( \sqrt{45} \) + \( 2 \)\( \sqrt{5} \)
| 6\( \sqrt{5} \) | |
| 14\( \sqrt{5} \) | |
| 8\( \sqrt{45} \) | |
| 6\( \sqrt{9} \) |
To add these radicals together their radicands must be the same:
4\( \sqrt{45} \) + 2\( \sqrt{5} \)
4\( \sqrt{9 \times 5} \) + 2\( \sqrt{5} \)
4\( \sqrt{3^2 \times 5} \) + 2\( \sqrt{5} \)
(4)(3)\( \sqrt{5} \) + 2\( \sqrt{5} \)
12\( \sqrt{5} \) + 2\( \sqrt{5} \)
Now that the radicands are identical, you can add them together:
12\( \sqrt{5} \) + 2\( \sqrt{5} \)