| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.95 |
| Score | 0% | 59% |
What is \( \frac{-3c^6}{1c^3} \)?
| -3c18 | |
| -\(\frac{1}{3}\)c-3 | |
| -3c3 | |
| -\(\frac{1}{3}\)c3 |
To divide terms with exponents, the base of both exponents must be the same. In this case they are so divide the coefficients and subtract the exponents:
\( \frac{-3c^6}{c^3} \)
\( \frac{-3}{1} \) c(6 - 3)
-3c3
The __________ is the smallest positive integer that is a multiple of two or more integers.
greatest common factor |
|
absolute value |
|
least common multiple |
|
least common factor |
The least common multiple (LCM) is the smallest positive integer that is a multiple of two or more integers.
Betty scored 83% on her final exam. If each question was worth 2 points and there were 180 possible points on the exam, how many questions did Betty answer correctly?
| 70 | |
| 75 | |
| 71 | |
| 86 |
Betty scored 83% on the test meaning she earned 83% of the possible points on the test. There were 180 possible points on the test so she earned 180 x 0.83 = 150 points. Each question is worth 2 points so she got \( \frac{150}{2} \) = 75 questions right.
A tiger in a zoo has consumed 99 pounds of food in 11 days. If the tiger continues to eat at the same rate, in how many more days will its total food consumtion be 135 pounds?
| 10 | |
| 11 | |
| 12 | |
| 4 |
If the tiger has consumed 99 pounds of food in 11 days that's \( \frac{99}{11} \) = 9 pounds of food per day. The tiger needs to consume 135 - 99 = 36 more pounds of food to reach 135 pounds total. At 9 pounds of food per day that's \( \frac{36}{9} \) = 4 more days.
Solve for \( \frac{3!}{5!} \)
| \( \frac{1}{20} \) | |
| \( \frac{1}{336} \) | |
| 42 | |
| 8 |
A factorial is the product of an integer and all the positive integers below it. To solve a fraction featuring factorials, expand the factorials and cancel out like numbers:
\( \frac{3!}{5!} \)
\( \frac{3 \times 2 \times 1}{5 \times 4 \times 3 \times 2 \times 1} \)
\( \frac{1}{5 \times 4} \)
\( \frac{1}{20} \)