To subtract these fractions, first find the lowest common multiple of their denominators. The first few multiples of 6 are [6, 12, 18, 24, 30, 36, 42, 48, 54, 60] and the first few multiples of 10 are [10, 20, 30, 40, 50, 60, 70, 80, 90]. The first few multiples they share are [30, 60, 90] making 30 the smallest multiple 6 and 10 share.

Next, convert the fractions so each denominator equals the lowest common multiple:

\( \frac{5 x 5}{6 x 5} \) - \( \frac{5 x 3}{10 x 3} \)

\( \frac{25}{30} \) - \( \frac{15}{30} \)

Now, because the fractions share a common denominator, you can subtract them:

\( \frac{25 - 15}{30} \) = \( \frac{10}{30} \) = \(\frac{1}{3}\)

The yearly interest charged on this loan is the annual interest rate multiplied by the amount borrowed:

interest = annual interest rate x loan amount

i = (\( \frac{6}{100} \)) x $400
i = 0.09 x $400
i = $36

By buying two shirts, Monty will save $35 x \( \frac{50}{100} \) = \( \frac{$35 x 50}{100} \) = \( \frac{$1750}{100} \) = $17.50 on the second shirt.

Use PEMDAS (Parentheses, Exponents, Multipy/Divide, Add/Subtract):

3 + (4 + 2) ÷ 2 x 4 - 5²
P: 3 + (6) ÷ 2 x 4 - 5²
E: 3 + 6 ÷ 2 x 4 - 25
MD: 3 + \( \frac{6}{2} \) x 4 - 25
MD: 3 + \( \frac{24}{2} \) - 25
AS: \( \frac{6}{2} \) + \( \frac{24}{2} \) - 25
AS: \( \frac{30}{2} \) - 25
AS: \( \frac{30 - 50}{2} \)
\( \frac{-20}{2} \)
-10

To add or subtract terms with exponents, both the base and the exponent must be the same. In this case they are so subtract the coefficients and retain the base and exponent:

3z² - 6z²
(3 - 6)z²
-3z²