ASVAB Arithmetic Reasoning Practice Test 660648 Results

Your Results Global Average
Questions 5 5
Correct 0 3.03
Score 0% 61%

Review

1

What is the greatest common factor of 44 and 68?

77% Answer Correctly
6
24
4
5

Solution

The factors of 44 are [1, 2, 4, 11, 22, 44] and the factors of 68 are [1, 2, 4, 17, 34, 68]. They share 3 factors [1, 2, 4] making 4 the greatest factor 44 and 68 have in common.


2

What is \( 5 \)\( \sqrt{125} \) + \( 3 \)\( \sqrt{5} \)

35% Answer Correctly
28\( \sqrt{5} \)
15\( \sqrt{625} \)
8\( \sqrt{125} \)
15\( \sqrt{5} \)

Solution

To add these radicals together their radicands must be the same:

5\( \sqrt{125} \) + 3\( \sqrt{5} \)
5\( \sqrt{25 \times 5} \) + 3\( \sqrt{5} \)
5\( \sqrt{5^2 \times 5} \) + 3\( \sqrt{5} \)
(5)(5)\( \sqrt{5} \) + 3\( \sqrt{5} \)
25\( \sqrt{5} \) + 3\( \sqrt{5} \)

Now that the radicands are identical, you can add them together:

25\( \sqrt{5} \) + 3\( \sqrt{5} \)
(25 + 3)\( \sqrt{5} \)
28\( \sqrt{5} \)


3

A triathlon course includes a 100m swim, a 30.9km bike ride, and a 6.4km run. What is the total length of the race course?

69% Answer Correctly
37.4km
54.9km
37.2km
59.5km

Solution

To add these distances, they must share the same unit so first you need to first convert the swim distance from meters (m) to kilometers (km) before adding it to the bike and run distances which are already in km. To convert 100 meters to kilometers, divide the distance by 1000 to get 0.1km then add the remaining distances:

total distance = swim + bike + run
total distance = 0.1km + 30.9km + 6.4km
total distance = 37.4km


4

What is 5x3 + 7x3?

66% Answer Correctly
12x3
12x6
2x3
2x-3

Solution

To add or subtract terms with exponents, both the base and the exponent must be the same. In this case they are so add the coefficients and retain the base and exponent:

5x3 + 7x3
(5 + 7)x3
12x3


5

If all of a roofing company's 15 workers are required to staff 5 roofing crews, how many workers need to be added during the busy season in order to send 7 complete crews out on jobs?

55% Answer Correctly
18
6
7
3

Solution

In order to find how many additional workers are needed to staff the extra crews you first need to calculate how many workers are on a crew. There are 15 workers at the company now and that's enough to staff 5 crews so there are \( \frac{15}{5} \) = 3 workers on a crew. 7 crews are needed for the busy season which, at 3 workers per crew, means that the roofing company will need 7 x 3 = 21 total workers to staff the crews during the busy season. The company already employs 15 workers so they need to add 21 - 15 = 6 new staff for the busy season.