To subtract these fractions, first find the lowest common multiple of their denominators. The first few multiples of 2 are [2, 4, 6, 8, 10, 12, 14, 16, 18, 20] and the first few multiples of 8 are [8, 16, 24, 32, 40, 48, 56, 64, 72, 80]. The first few multiples they share are [8, 16, 24, 32, 40] making 8 the smallest multiple 2 and 8 share.

Next, convert the fractions so each denominator equals the lowest common multiple:

\( \frac{2 x 4}{2 x 4} \) - \( \frac{4 x 1}{8 x 1} \)

\( \frac{8}{8} \) - \( \frac{4}{8} \)

Now, because the fractions share a common denominator, you can subtract them:

\( \frac{8 - 4}{8} \) = \( \frac{4}{8} \) = \(\frac{1}{2}\)

To add or subtract terms with exponents, both the base and the exponent must be the same. In this case they are so add the coefficients and retain the base and exponent:

-7a² + 3a²
(-7 + 3)a²
-4a²

A prime number is an integer greater than 1 that has no factors other than 1 and itself. Examples of prime numbers include 2, 3, 5, 7, and 11.

If the tiger has consumed 56 pounds of food in 8 days that's \( \frac{56}{8} \) = 7 pounds of food per day. The tiger needs to consume 98 - 56 = 42 more pounds of food to reach 98 pounds total. At 7 pounds of food per day that's \( \frac{42}{7} \) = 6 more days.

The distributive property for division helps in solving expressions like \({b + c \over a}\). It specifies that the result of dividing a fraction with multiple terms in the numerator and one term in the denominator can be obtained by dividing each term individually and then totaling the results: \({b + c \over a} = {b \over a} + {c \over a}\). For example, \({a^3 + 6a^2 \over a^2} = {a^3 \over a^2} + {6a^2 \over a^2} = a + 6\).