| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.18 |
| Score | 0% | 64% |
If a rectangle is twice as long as it is wide and has a perimeter of 54 meters, what is the area of the rectangle?
| 98 m2 | |
| 18 m2 | |
| 32 m2 | |
| 162 m2 |
The area of a rectangle is width (w) x height (h). In this problem we know that the rectangle is twice as long as it is wide so h = 2w. The perimeter of a rectangle is 2w + 2h and we know that the perimeter of this rectangle is 54 meters so the equation becomes: 2w + 2h = 54.
Putting these two equations together and solving for width (w):
2w + 2h = 54
w + h = \( \frac{54}{2} \)
w + h = 27
w = 27 - h
From the question we know that h = 2w so substituting 2w for h gives us:
w = 27 - 2w
3w = 27
w = \( \frac{27}{3} \)
w = 9
Since h = 2w that makes h = (2 x 9) = 18 and the area = h x w = 9 x 18 = 162 m2
Convert c-2 to remove the negative exponent.
| \( \frac{2}{c} \) | |
| \( \frac{1}{c^2} \) | |
| \( \frac{-1}{c^{-2}} \) | |
| \( \frac{1}{c^{-2}} \) |
To convert a negative exponent to a positive exponent, calculate the positive exponent then take the reciprocal.
Solve for \( \frac{4!}{3!} \)
| \( \frac{1}{56} \) | |
| \( \frac{1}{30} \) | |
| \( \frac{1}{3024} \) | |
| 4 |
A factorial is the product of an integer and all the positive integers below it. To solve a fraction featuring factorials, expand the factorials and cancel out like numbers:
\( \frac{4!}{3!} \)
\( \frac{4 \times 3 \times 2 \times 1}{3 \times 2 \times 1} \)
\( \frac{4}{1} \)
4
The __________ is the greatest factor that divides two integers.
least common multiple |
|
greatest common multiple |
|
absolute value |
|
greatest common factor |
The greatest common factor (GCF) is the greatest factor that divides two integers.
A menswear store is having a sale: "Buy one shirt at full price and get another shirt for 20% off." If Alex buys two shirts, each with a regular price of $14, how much money will he save?
| $2.80 | |
| $0.70 | |
| $1.40 | |
| $5.60 |
By buying two shirts, Alex will save $14 x \( \frac{20}{100} \) = \( \frac{$14 x 20}{100} \) = \( \frac{$280}{100} \) = $2.80 on the second shirt.