| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.75 |
| Score | 0% | 55% |
A menswear store is having a sale: "Buy one shirt at full price and get another shirt for 20% off." If Charlie buys two shirts, each with a regular price of $43, how much will he pay for both shirts?
| $8.60 | |
| $77.40 | |
| $55.90 | |
| $34.40 |
By buying two shirts, Charlie will save $43 x \( \frac{20}{100} \) = \( \frac{$43 x 20}{100} \) = \( \frac{$860}{100} \) = $8.60 on the second shirt.
So, his total cost will be
$43.00 + ($43.00 - $8.60)
$43.00 + $34.40
$77.40
A circular logo is enlarged to fit the lid of a jar. The new diameter is 60% larger than the original. By what percentage has the area of the logo increased?
| 30% | |
| 20% | |
| 25% | |
| 32\(\frac{1}{2}\)% |
The area of a circle is given by the formula A = πr2 where r is the radius of the circle. The radius of a circle is its diameter divided by two so A = π(\( \frac{d}{2} \))2. If the diameter of the logo increases by 60% the radius (and, consequently, the total area) increases by \( \frac{60\text{%}}{2} \) = 30%
A tiger in a zoo has consumed 108 pounds of food in 9 days. If the tiger continues to eat at the same rate, in how many more days will its total food consumtion be 156 pounds?
| 3 | |
| 2 | |
| 4 | |
| 7 |
If the tiger has consumed 108 pounds of food in 9 days that's \( \frac{108}{9} \) = 12 pounds of food per day. The tiger needs to consume 156 - 108 = 48 more pounds of food to reach 156 pounds total. At 12 pounds of food per day that's \( \frac{48}{12} \) = 4 more days.
13 members of a bridal party need transported to a wedding reception but there are only 3 3-passenger taxis available to take them. How many will need to find other transportation?
| 9 | |
| 3 | |
| 6 | |
| 4 |
There are 3 3-passenger taxis available so that's 3 x 3 = 9 total seats. There are 13 people needing transportation leaving 13 - 9 = 4 who will have to find other transportation.
What is \( 8 \)\( \sqrt{18} \) + \( 4 \)\( \sqrt{2} \)
| 28\( \sqrt{2} \) | |
| 32\( \sqrt{2} \) | |
| 12\( \sqrt{18} \) | |
| 12\( \sqrt{36} \) |
To add these radicals together their radicands must be the same:
8\( \sqrt{18} \) + 4\( \sqrt{2} \)
8\( \sqrt{9 \times 2} \) + 4\( \sqrt{2} \)
8\( \sqrt{3^2 \times 2} \) + 4\( \sqrt{2} \)
(8)(3)\( \sqrt{2} \) + 4\( \sqrt{2} \)
24\( \sqrt{2} \) + 4\( \sqrt{2} \)
Now that the radicands are identical, you can add them together:
24\( \sqrt{2} \) + 4\( \sqrt{2} \)