| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.28 |
| Score | 0% | 66% |
What is \( \frac{3}{6} \) x \( \frac{2}{5} \)?
| \(\frac{1}{5}\) | |
| \(\frac{4}{49}\) | |
| \(\frac{1}{27}\) | |
| 1\(\frac{1}{5}\) |
To multiply fractions, multiply the numerators together and then multiply the denominators together:
\( \frac{3}{6} \) x \( \frac{2}{5} \) = \( \frac{3 x 2}{6 x 5} \) = \( \frac{6}{30} \) = \(\frac{1}{5}\)
What is -9b4 x 4b6?
| -36b4 | |
| -36b2 | |
| -5b4 | |
| -36b10 |
To multiply terms with exponents, the base of both exponents must be the same. In this case they are so multiply the coefficients and add the exponents:
-9b4 x 4b6
(-9 x 4)b(4 + 6)
-36b10
a(b + c) = ab + ac defines which of the following?
distributive property for division |
|
commutative property for multiplication |
|
distributive property for multiplication |
|
commutative property for division |
The distributive property for multiplication helps in solving expressions like a(b + c). It specifies that the result of multiplying one number by the sum or difference of two numbers can be obtained by multiplying each number individually and then totaling the results: a(b + c) = ab + ac. For example, 4(10-5) = (4 x 10) - (4 x 5) = 40 - 20 = 20.
How many 1 gallon cans worth of fuel would you need to pour into an empty 10 gallon tank to fill it exactly halfway?
| 8 | |
| 10 | |
| 4 | |
| 5 |
To fill a 10 gallon tank exactly halfway you'll need 5 gallons of fuel. Each fuel can holds 1 gallons so:
cans = \( \frac{5 \text{ gallons}}{1 \text{ gallons}} \) = 5
\({b + c \over a} = {b \over a} + {c \over a}\) defines which of the following?
distributive property for multiplication |
|
distributive property for division |
|
commutative property for division |
|
commutative property for multiplication |
The distributive property for division helps in solving expressions like \({b + c \over a}\). It specifies that the result of dividing a fraction with multiple terms in the numerator and one term in the denominator can be obtained by dividing each term individually and then totaling the results: \({b + c \over a} = {b \over a} + {c \over a}\). For example, \({a^3 + 6a^2 \over a^2} = {a^3 \over a^2} + {6a^2 \over a^2} = a + 6\).