| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.11 |
| Score | 0% | 62% |
\({b + c \over a} = {b \over a} + {c \over a}\) defines which of the following?
distributive property for multiplication |
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commutative property for multiplication |
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commutative property for division |
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distributive property for division |
The distributive property for division helps in solving expressions like \({b + c \over a}\). It specifies that the result of dividing a fraction with multiple terms in the numerator and one term in the denominator can be obtained by dividing each term individually and then totaling the results: \({b + c \over a} = {b \over a} + {c \over a}\). For example, \({a^3 + 6a^2 \over a^2} = {a^3 \over a^2} + {6a^2 \over a^2} = a + 6\).
If a mayor is elected with 67% of the votes cast and 87% of a town's 14,000 voters cast a vote, how many votes did the mayor receive?
| 10,962 | |
| 8,161 | |
| 7,064 | |
| 10,109 |
If 87% of the town's 14,000 voters cast ballots the number of votes cast is:
(\( \frac{87}{100} \)) x 14,000 = \( \frac{1,218,000}{100} \) = 12,180
The mayor got 67% of the votes cast which is:
(\( \frac{67}{100} \)) x 12,180 = \( \frac{816,060}{100} \) = 8,161 votes.
What is \( \frac{7b^7}{6b^3} \)?
| \(\frac{6}{7}\)b-4 | |
| \(\frac{6}{7}\)b10 | |
| 1\(\frac{1}{6}\)b4 | |
| 1\(\frac{1}{6}\)b10 |
To divide terms with exponents, the base of both exponents must be the same. In this case they are so divide the coefficients and subtract the exponents:
\( \frac{7b^7}{6b^3} \)
\( \frac{7}{6} \) b(7 - 3)
1\(\frac{1}{6}\)b4
What is \( \sqrt{\frac{16}{9}} \)?
| \(\frac{7}{8}\) | |
| \(\frac{5}{7}\) | |
| 1\(\frac{1}{3}\) | |
| 1\(\frac{2}{5}\) |
To take the square root of a fraction, break the fraction into two separate roots then calculate the square root of the numerator and denominator separately:
\( \sqrt{\frac{16}{9}} \)
\( \frac{\sqrt{16}}{\sqrt{9}} \)
\( \frac{\sqrt{4^2}}{\sqrt{3^2}} \)
\( \frac{4}{3} \)
1\(\frac{1}{3}\)
What is -y5 x 4y2?
| -4y3 | |
| 3y10 | |
| -4y2 | |
| -4y7 |
To multiply terms with exponents, the base of both exponents must be the same. In this case they are so multiply the coefficients and add the exponents:
-y5 x 4y2
(-1 x 4)y(5 + 2)
-4y7