ASVAB Arithmetic Reasoning Practice Test 671706 Results

Your Results Global Average
Questions 5 5
Correct 0 3.24
Score 0% 65%

Review

1

A bread recipe calls for 3\(\frac{1}{2}\) cups of flour. If you only have 1 cup, how much more flour is needed?

62% Answer Correctly
3\(\frac{1}{8}\) cups
1\(\frac{1}{4}\) cups
\(\frac{1}{8}\) cups
2\(\frac{1}{2}\) cups

Solution

The amount of flour you need is (3\(\frac{1}{2}\) - 1) cups. Rewrite the quantities so they share a common denominator and subtract:

(\( \frac{28}{8} \) - \( \frac{8}{8} \)) cups
\( \frac{20}{8} \) cups
2\(\frac{1}{2}\) cups


2

What is 2b2 - 4b2?

71% Answer Correctly
-2b2
6b-4
6b4
6b2

Solution

To add or subtract terms with exponents, both the base and the exponent must be the same. In this case they are so subtract the coefficients and retain the base and exponent:

2b2 - 4b2
(2 - 4)b2
-2b2


3

If all of a roofing company's 10 workers are required to staff 5 roofing crews, how many workers need to be added during the busy season in order to send 8 complete crews out on jobs?

55% Answer Correctly
6
5
2
18

Solution

In order to find how many additional workers are needed to staff the extra crews you first need to calculate how many workers are on a crew. There are 10 workers at the company now and that's enough to staff 5 crews so there are \( \frac{10}{5} \) = 2 workers on a crew. 8 crews are needed for the busy season which, at 2 workers per crew, means that the roofing company will need 8 x 2 = 16 total workers to staff the crews during the busy season. The company already employs 10 workers so they need to add 16 - 10 = 6 new staff for the busy season.


4

What is -a6 x 7a5?

75% Answer Correctly
6a5
-7a11
6a6
-7a-1

Solution

To multiply terms with exponents, the base of both exponents must be the same. In this case they are so multiply the coefficients and add the exponents:

-a6 x 7a5
(-1 x 7)a(6 + 5)
-7a11


5

If \( \left|c - 6\right| \) - 3 = -6, which of these is a possible value for c?

62% Answer Correctly
9
1
-8
-3

Solution

First, solve for \( \left|c - 6\right| \):

\( \left|c - 6\right| \) - 3 = -6
\( \left|c - 6\right| \) = -6 + 3
\( \left|c - 6\right| \) = -3

The value inside the absolute value brackets can be either positive or negative so (c - 6) must equal - 3 or --3 for \( \left|c - 6\right| \) to equal -3:

c - 6 = -3
c = -3 + 6
c = 3
c - 6 = 3
c = 3 + 6
c = 9

So, c = 9 or c = 3.