A factorial is the product of an integer and all the positive integers below it. To solve a fraction featuring factorials, expand the factorials and cancel out like numbers:

\( \frac{5!}{2!} \)
\( \frac{5 \times 4 \times 3 \times 2 \times 1}{2 \times 1} \)
\( \frac{5 \times 4 \times 3}{1} \)
\( 5 \times 4 \times 3 \)
60

To simplify a radical, factor out the perfect squares:

\( \sqrt{175} \)
\( \sqrt{25 \times 7} \)
\( \sqrt{5^2 \times 7} \)
5\( \sqrt{7} \)

guard shots made = shots taken x \( \frac{\text{% made}}{100} \) = 15 x \( \frac{35}{100} \) = \( \frac{35 x 15}{100} \) = \( \frac{525}{100} \) = 5 shots

The center makes 25% of his shots so he'll have to take:

shots made = shots taken x \( \frac{\text{% made}}{100} \)
shots taken = \( \frac{\text{shots taken}}{\frac{\text{% made}}{100}} \)

to make as many shots as the guard. Plugging in values for the center gives us:

center shots taken = \( \frac{5}{\frac{25}{100}} \) = 5 x \( \frac{100}{25} \) = \( \frac{5 x 100}{25} \) = \( \frac{500}{25} \) = 20 shots

to make the same number of shots as the guard and thus score the same number of points.

Calculate the number of vans needed by dividing the number of people that need transported by the capacity of one van:

vans = \( \frac{90}{11} \) = 8\(\frac{2}{11}\)

So, it will take 8 full vans and one partially full van to transport the entire team making a total of 9 vans.

To add or subtract terms with exponents, both the base and the exponent must be the same. In this case they are so add the coefficients and retain the base and exponent:

2y⁵ + 3y⁵
(2 + 3)y⁵
5y⁵