| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.22 |
| Score | 0% | 64% |
If \( \left|y + 0\right| \) + 7 = 5, which of these is a possible value for y?
| 1 | |
| 4 | |
| 2 | |
| -11 |
First, solve for \( \left|y + 0\right| \):
\( \left|y + 0\right| \) + 7 = 5
\( \left|y + 0\right| \) = 5 - 7
\( \left|y + 0\right| \) = -2
The value inside the absolute value brackets can be either positive or negative so (y + 0) must equal - 2 or --2 for \( \left|y + 0\right| \) to equal -2:
| y + 0 = -2 y = -2 + 0 y = -2 | y + 0 = 2 y = 2 + 0 y = 2 |
So, y = 2 or y = -2.
What is -6b2 + 3b2?
| -9b2 | |
| 9b-2 | |
| -3b-4 | |
| -3b2 |
To add or subtract terms with exponents, both the base and the exponent must be the same. In this case they are so add the coefficients and retain the base and exponent:
-6b2 + 3b2
(-6 + 3)b2
-3b2
Bob loaned Monty $200 at an annual interest rate of 6%. If no payments are made, what is the interest owed on this loan at the end of the first year?
| $36 | |
| $30 | |
| $12 | |
| $18 |
The yearly interest charged on this loan is the annual interest rate multiplied by the amount borrowed:
interest = annual interest rate x loan amount
i = (\( \frac{6}{100} \)) x $200
i = 0.06 x $200
i = $12
Which of the following is a mixed number?
\({a \over 5} \) |
|
\({5 \over 7} \) |
|
\(1 {2 \over 5} \) |
|
\({7 \over 5} \) |
A rational number (or fraction) is represented as a ratio between two integers, a and b, and has the form \({a \over b}\) where a is the numerator and b is the denominator. An improper fraction (\({5 \over 3} \)) has a numerator with a greater absolute value than the denominator and can be converted into a mixed number (\(1 {2 \over 3} \)) which has a whole number part and a fractional part.
What is \( 9 \)\( \sqrt{50} \) + \( 4 \)\( \sqrt{2} \)
| 36\( \sqrt{25} \) | |
| 49\( \sqrt{2} \) | |
| 13\( \sqrt{2} \) | |
| 13\( \sqrt{100} \) |
To add these radicals together their radicands must be the same:
9\( \sqrt{50} \) + 4\( \sqrt{2} \)
9\( \sqrt{25 \times 2} \) + 4\( \sqrt{2} \)
9\( \sqrt{5^2 \times 2} \) + 4\( \sqrt{2} \)
(9)(5)\( \sqrt{2} \) + 4\( \sqrt{2} \)
45\( \sqrt{2} \) + 4\( \sqrt{2} \)
Now that the radicands are identical, you can add them together:
45\( \sqrt{2} \) + 4\( \sqrt{2} \)