| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.95 |
| Score | 0% | 59% |
How many 12-passenger vans will it take to drive all 50 members of the football team to an away game?
| 6 vans | |
| 5 vans | |
| 8 vans | |
| 9 vans |
Calculate the number of vans needed by dividing the number of people that need transported by the capacity of one van:
vans = \( \frac{50}{12} \) = 4\(\frac{1}{6}\)
So, it will take 4 full vans and one partially full van to transport the entire team making a total of 5 vans.
A bread recipe calls for 2\(\frac{3}{8}\) cups of flour. If you only have \(\frac{7}{8}\) cup, how much more flour is needed?
| 1\(\frac{1}{4}\) cups | |
| 1\(\frac{1}{2}\) cups | |
| 1\(\frac{3}{8}\) cups | |
| 2\(\frac{1}{4}\) cups |
The amount of flour you need is (2\(\frac{3}{8}\) - \(\frac{7}{8}\)) cups. Rewrite the quantities so they share a common denominator and subtract:
(\( \frac{19}{8} \) - \( \frac{7}{8} \)) cups
\( \frac{12}{8} \) cups
1\(\frac{1}{2}\) cups
What is 7\( \sqrt{6} \) x 9\( \sqrt{6} \)?
| 378 | |
| 16\( \sqrt{6} \) | |
| 16\( \sqrt{36} \) | |
| 63\( \sqrt{6} \) |
To multiply terms with radicals, multiply the coefficients and radicands separately:
7\( \sqrt{6} \) x 9\( \sqrt{6} \)
(7 x 9)\( \sqrt{6 \times 6} \)
63\( \sqrt{36} \)
Now we need to simplify the radical:
63\( \sqrt{36} \)
63\( \sqrt{6^2} \)
(63)(6)
378
What is \( \frac{6y^8}{7y^2} \)?
| 1\(\frac{1}{6}\)y10 | |
| \(\frac{6}{7}\)y16 | |
| \(\frac{6}{7}\)y\(\frac{1}{4}\) | |
| \(\frac{6}{7}\)y6 |
To divide terms with exponents, the base of both exponents must be the same. In this case they are so divide the coefficients and subtract the exponents:
\( \frac{6y^8}{7y^2} \)
\( \frac{6}{7} \) y(8 - 2)
\(\frac{6}{7}\)y6
A circular logo is enlarged to fit the lid of a jar. The new diameter is 75% larger than the original. By what percentage has the area of the logo increased?
| 22\(\frac{1}{2}\)% | |
| 32\(\frac{1}{2}\)% | |
| 30% | |
| 37\(\frac{1}{2}\)% |
The area of a circle is given by the formula A = πr2 where r is the radius of the circle. The radius of a circle is its diameter divided by two so A = π(\( \frac{d}{2} \))2. If the diameter of the logo increases by 75% the radius (and, consequently, the total area) increases by \( \frac{75\text{%}}{2} \) = 37\(\frac{1}{2}\)%