ASVAB Arithmetic Reasoning Practice Test 676104 Results

Your Results Global Average
Questions 5 5
Correct 0 3.71
Score 0% 74%

Review

1

What is the least common multiple of 6 and 8?

72% Answer Correctly
17
24
28
4

Solution

The first few multiples of 6 are [6, 12, 18, 24, 30, 36, 42, 48, 54, 60] and the first few multiples of 8 are [8, 16, 24, 32, 40, 48, 56, 64, 72, 80]. The first few multiples they share are [24, 48, 72, 96] making 24 the smallest multiple 6 and 8 have in common.


2

What is the distance in miles of a trip that takes 9 hours at an average speed of 15 miles per hour?

87% Answer Correctly
135 miles
220 miles
525 miles
350 miles

Solution

Average speed in miles per hour is the number of miles traveled divided by the number of hours:

speed = \( \frac{\text{distance}}{\text{time}} \)

Solving for distance:

distance = \( \text{speed} \times \text{time} \)
distance = \( 15mph \times 9h \)
135 miles


3

4! = ?

84% Answer Correctly

5 x 4 x 3 x 2 x 1

3 x 2 x 1

4 x 3

4 x 3 x 2 x 1


Solution

A factorial has the form n! and is the product of the integer (n) and all the positive integers below it. For example, 5! = 5 x 4 x 3 x 2 x 1 = 120.


4

Monty loaned Charlie $1,000 at an annual interest rate of 4%. If no payments are made, what is the interest owed on this loan at the end of the first year?

74% Answer Correctly
$9
$55
$40
$5

Solution

The yearly interest charged on this loan is the annual interest rate multiplied by the amount borrowed:

interest = annual interest rate x loan amount

i = (\( \frac{6}{100} \)) x $1,000
i = 0.04 x $1,000
i = $40


5

If all of a roofing company's 8 workers are required to staff 4 roofing crews, how many workers need to be added during the busy season in order to send 7 complete crews out on jobs?

55% Answer Correctly
6
8
9
17

Solution

In order to find how many additional workers are needed to staff the extra crews you first need to calculate how many workers are on a crew. There are 8 workers at the company now and that's enough to staff 4 crews so there are \( \frac{8}{4} \) = 2 workers on a crew. 7 crews are needed for the busy season which, at 2 workers per crew, means that the roofing company will need 7 x 2 = 14 total workers to staff the crews during the busy season. The company already employs 8 workers so they need to add 14 - 8 = 6 new staff for the busy season.