| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.89 |
| Score | 0% | 58% |
What is the greatest common factor of 32 and 40?
| 25 | |
| 21 | |
| 9 | |
| 8 |
The factors of 32 are [1, 2, 4, 8, 16, 32] and the factors of 40 are [1, 2, 4, 5, 8, 10, 20, 40]. They share 4 factors [1, 2, 4, 8] making 8 the greatest factor 32 and 40 have in common.
Simplify \( \sqrt{20} \)
| 2\( \sqrt{10} \) | |
| 5\( \sqrt{10} \) | |
| 6\( \sqrt{10} \) | |
| 2\( \sqrt{5} \) |
To simplify a radical, factor out the perfect squares:
\( \sqrt{20} \)
\( \sqrt{4 \times 5} \)
\( \sqrt{2^2 \times 5} \)
2\( \sqrt{5} \)
What is \( \frac{3c^8}{2c^2} \)?
| \(\frac{2}{3}\)c-6 | |
| 1\(\frac{1}{2}\)c16 | |
| 1\(\frac{1}{2}\)c6 | |
| 1\(\frac{1}{2}\)c4 |
To divide terms with exponents, the base of both exponents must be the same. In this case they are so divide the coefficients and subtract the exponents:
\( \frac{3c^8}{2c^2} \)
\( \frac{3}{2} \) c(8 - 2)
1\(\frac{1}{2}\)c6
If a mayor is elected with 89% of the votes cast and 69% of a town's 15,000 voters cast a vote, how many votes did the mayor receive?
| 6,728 | |
| 7,142 | |
| 9,211 | |
| 5,279 |
If 69% of the town's 15,000 voters cast ballots the number of votes cast is:
(\( \frac{69}{100} \)) x 15,000 = \( \frac{1,035,000}{100} \) = 10,350
The mayor got 89% of the votes cast which is:
(\( \frac{89}{100} \)) x 10,350 = \( \frac{921,150}{100} \) = 9,211 votes.
What is \( 7 \)\( \sqrt{80} \) - \( 9 \)\( \sqrt{5} \)
| 19\( \sqrt{5} \) | |
| 63\( \sqrt{16} \) | |
| 63\( \sqrt{5} \) | |
| -2\( \sqrt{400} \) |
To subtract these radicals together their radicands must be the same:
7\( \sqrt{80} \) - 9\( \sqrt{5} \)
7\( \sqrt{16 \times 5} \) - 9\( \sqrt{5} \)
7\( \sqrt{4^2 \times 5} \) - 9\( \sqrt{5} \)
(7)(4)\( \sqrt{5} \) - 9\( \sqrt{5} \)
28\( \sqrt{5} \) - 9\( \sqrt{5} \)
Now that the radicands are identical, you can subtract them:
28\( \sqrt{5} \) - 9\( \sqrt{5} \)