| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.87 |
| Score | 0% | 57% |
A sports card collection contains football, baseball, and basketball cards. If the ratio of football to baseball cards is 7 to 2 and the ratio of baseball to basketball cards is 7 to 1, what is the ratio of football to basketball cards?
| 5:1 | |
| 1:4 | |
| 49:2 | |
| 9:6 |
The ratio of football cards to baseball cards is 7:2 and the ratio of baseball cards to basketball cards is 7:1. To solve this problem, we need the baseball card side of each ratio to be equal so we need to rewrite the ratios in terms of a common number of baseball cards. (Think of this like finding the common denominator when adding fractions.) The ratio of football to baseball cards can also be written as 49:14 and the ratio of baseball cards to basketball cards as 14:2. So, the ratio of football cards to basketball cards is football:baseball, baseball:basketball or 49:14, 14:2 which reduces to 49:2.
What is 6y7 x 6y6?
| 36y42 | |
| 36y | |
| 36y13 | |
| 36y6 |
To multiply terms with exponents, the base of both exponents must be the same. In this case they are so multiply the coefficients and add the exponents:
6y7 x 6y6
(6 x 6)y(7 + 6)
36y13
A circular logo is enlarged to fit the lid of a jar. The new diameter is 60% larger than the original. By what percentage has the area of the logo increased?
| 30% | |
| 35% | |
| 27\(\frac{1}{2}\)% | |
| 37\(\frac{1}{2}\)% |
The area of a circle is given by the formula A = πr2 where r is the radius of the circle. The radius of a circle is its diameter divided by two so A = π(\( \frac{d}{2} \))2. If the diameter of the logo increases by 60% the radius (and, consequently, the total area) increases by \( \frac{60\text{%}}{2} \) = 30%
Damon loaned Frank $1,000 at an annual interest rate of 9%. If no payments are made, what is the interest owed on this loan at the end of the first year?
| $96 | |
| $77 | |
| $90 | |
| $80 |
The yearly interest charged on this loan is the annual interest rate multiplied by the amount borrowed:
interest = annual interest rate x loan amount
i = (\( \frac{6}{100} \)) x $1,000
i = 0.09 x $1,000
i = $90
What is \( 3 \)\( \sqrt{125} \) + \( 2 \)\( \sqrt{5} \)
| 5\( \sqrt{125} \) | |
| 6\( \sqrt{625} \) | |
| 5\( \sqrt{25} \) | |
| 17\( \sqrt{5} \) |
To add these radicals together their radicands must be the same:
3\( \sqrt{125} \) + 2\( \sqrt{5} \)
3\( \sqrt{25 \times 5} \) + 2\( \sqrt{5} \)
3\( \sqrt{5^2 \times 5} \) + 2\( \sqrt{5} \)
(3)(5)\( \sqrt{5} \) + 2\( \sqrt{5} \)
15\( \sqrt{5} \) + 2\( \sqrt{5} \)
Now that the radicands are identical, you can add them together:
15\( \sqrt{5} \) + 2\( \sqrt{5} \)