ASVAB Arithmetic Reasoning Practice Test 683789 Results

Your Results Global Average
Questions 5 5
Correct 0 2.97
Score 0% 59%

Review

1

Which of the following statements about exponents is false?

47% Answer Correctly

all of these are false

b1 = b

b1 = 1

b0 = 1


Solution

A number with an exponent (be) consists of a base (b) raised to a power (e). The exponent indicates the number of times that the base is multiplied by itself. A base with an exponent of 1 equals the base (b1 = b) and a base with an exponent of 0 equals 1 ( (b0 = 1).


2

This property states taht the order of addition or multiplication does not mater. For example, 2 + 5 and 5 + 2 are equivalent.

60% Answer Correctly

commutative

PEDMAS

distributive

associative


Solution

The commutative property states that, when adding or multiplying numbers, the order in which they're added or multiplied does not matter. For example, 3 + 4 and 4 + 3 give the same result, as do 3 x 4 and 4 x 3.


3

Christine scored 81% on her final exam. If each question was worth 4 points and there were 320 possible points on the exam, how many questions did Christine answer correctly?

57% Answer Correctly
58
78
65
62

Solution

Christine scored 81% on the test meaning she earned 81% of the possible points on the test. There were 320 possible points on the test so she earned 320 x 0.81 = 260 points. Each question is worth 4 points so she got \( \frac{260}{4} \) = 65 questions right.


4

What is \( \sqrt{\frac{49}{81}} \)?

70% Answer Correctly
\(\frac{7}{9}\)
\(\frac{7}{8}\)
4\(\frac{1}{2}\)
1\(\frac{1}{2}\)

Solution

To take the square root of a fraction, break the fraction into two separate roots then calculate the square root of the numerator and denominator separately:

\( \sqrt{\frac{49}{81}} \)
\( \frac{\sqrt{49}}{\sqrt{81}} \)
\( \frac{\sqrt{7^2}}{\sqrt{9^2}} \)
\(\frac{7}{9}\)


5

Solve for \( \frac{2!}{5!} \)

67% Answer Correctly
8
\( \frac{1}{4} \)
\( \frac{1}{60} \)
840

Solution

A factorial is the product of an integer and all the positive integers below it. To solve a fraction featuring factorials, expand the factorials and cancel out like numbers:

\( \frac{2!}{5!} \)
\( \frac{2 \times 1}{5 \times 4 \times 3 \times 2 \times 1} \)
\( \frac{1}{5 \times 4 \times 3} \)
\( \frac{1}{60} \)