| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.55 |
| Score | 0% | 51% |
What is 8\( \sqrt{8} \) x 6\( \sqrt{8} \)?
| 48\( \sqrt{16} \) | |
| 384 | |
| 14\( \sqrt{8} \) | |
| 14\( \sqrt{64} \) |
To multiply terms with radicals, multiply the coefficients and radicands separately:
8\( \sqrt{8} \) x 6\( \sqrt{8} \)
(8 x 6)\( \sqrt{8 \times 8} \)
48\( \sqrt{64} \)
Now we need to simplify the radical:
48\( \sqrt{64} \)
48\( \sqrt{8^2} \)
(48)(8)
384
Latoya scored 76% on her final exam. If each question was worth 4 points and there were 280 possible points on the exam, how many questions did Latoya answer correctly?
| 68 | |
| 57 | |
| 44 | |
| 53 |
Latoya scored 76% on the test meaning she earned 76% of the possible points on the test. There were 280 possible points on the test so she earned 280 x 0.76 = 212 points. Each question is worth 4 points so she got \( \frac{212}{4} \) = 53 questions right.
This property states taht the order of addition or multiplication does not mater. For example, 2 + 5 and 5 + 2 are equivalent.
associative |
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PEDMAS |
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distributive |
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commutative |
The commutative property states that, when adding or multiplying numbers, the order in which they're added or multiplied does not matter. For example, 3 + 4 and 4 + 3 give the same result, as do 3 x 4 and 4 x 3.
On average, the center for a basketball team hits 35% of his shots while a guard on the same team hits 50% of his shots. If the guard takes 10 shots during a game, how many shots will the center have to take to score as many points as the guard assuming each shot is worth the same number of points?
| 20 | |
| 16 | |
| 14 | |
| 17 |
guard shots made = shots taken x \( \frac{\text{% made}}{100} \) = 10 x \( \frac{50}{100} \) = \( \frac{50 x 10}{100} \) = \( \frac{500}{100} \) = 5 shots
The center makes 35% of his shots so he'll have to take:
shots made = shots taken x \( \frac{\text{% made}}{100} \)
shots taken = \( \frac{\text{shots taken}}{\frac{\text{% made}}{100}} \)
to make as many shots as the guard. Plugging in values for the center gives us:
center shots taken = \( \frac{5}{\frac{35}{100}} \) = 5 x \( \frac{100}{35} \) = \( \frac{5 x 100}{35} \) = \( \frac{500}{35} \) = 14 shots
to make the same number of shots as the guard and thus score the same number of points.
If all of a roofing company's 15 workers are required to staff 5 roofing crews, how many workers need to be added during the busy season in order to send 8 complete crews out on jobs?
| 13 | |
| 11 | |
| 7 | |
| 9 |
In order to find how many additional workers are needed to staff the extra crews you first need to calculate how many workers are on a crew. There are 15 workers at the company now and that's enough to staff 5 crews so there are \( \frac{15}{5} \) = 3 workers on a crew. 8 crews are needed for the busy season which, at 3 workers per crew, means that the roofing company will need 8 x 3 = 24 total workers to staff the crews during the busy season. The company already employs 15 workers so they need to add 24 - 15 = 9 new staff for the busy season.