ASVAB Arithmetic Reasoning Practice Test 686780 Results

	Your Results	Global Average
Questions	5	5
Correct	0	3.44
Score	0%	69%

Review

How many 9-passenger vans will it take to drive all 99 members of the football team to an away game?

80% Answer Correctly

	11 vans
	6 vans
	14 vans
	5 vans

Solution

Calculate the number of vans needed by dividing the number of people that need transported by the capacity of one van:

vans = $ \frac{99}{9} $ = 11

Which of the following is not a prime number?

65% Answer Correctly

	2
	7
	9
	5

Solution

A prime number is an integer greater than 1 that has no factors other than 1 and itself. Examples of prime numbers include 2, 3, 5, 7, and 11.

Bob loaned Diane $600 at an annual interest rate of 1%. If no payments are made, what is the total amount owed at the end of the first year?

71% Answer Correctly

	$606
	$624
	$618
	$648

Solution

The yearly interest charged on this loan is the annual interest rate multiplied by the amount borrowed:

interest = annual interest rate x loan amount

i = ($ \frac{6}{100} $) x $600
i = 0.01 x $600

No payments were made so the total amount due is the original amount + the accumulated interest:

total = $600 + $6
total = $606

Simplify $ \frac{32}{48} $.

77% Answer Correctly

	$ \frac{4}{15} $
	$ \frac{2}{3} $
	$ \frac{1}{2} $
	$ \frac{7}{19} $

Solution

To simplify this fraction, first find the greatest common factor between them. The factors of 32 are [1, 2, 4, 8, 16, 32] and the factors of 48 are [1, 2, 3, 4, 6, 8, 12, 16, 24, 48]. They share 5 factors [1, 2, 4, 8, 16] making 16 their greatest common factor (GCF).

Next, divide both numerator and denominator by the GCF:

$ \frac{32}{48} $ = $ \frac{\frac{32}{16}}{\frac{48}{16}} $ = $ \frac{2}{3} $

Solve 4 + (5 + 2) ÷ 5 x 2 - 2²

52% Answer Correctly

	1$\frac{2}{5}$
	$\frac{1}{3}$
	2$\frac{4}{5}$
	1

Solution

Use PEMDAS (Parentheses, Exponents, Multipy/Divide, Add/Subtract):

4 + (5 + 2) ÷ 5 x 2 - 2²
P: 4 + (7) ÷ 5 x 2 - 2²
E: 4 + 7 ÷ 5 x 2 - 4
MD: 4 + $ \frac{7}{5} $ x 2 - 4
MD: 4 + $ \frac{14}{5} $ - 4
AS: $ \frac{20}{5} $ + $ \frac{14}{5} $ - 4
AS: $ \frac{34}{5} $ - 4
AS: $ \frac{34 - 20}{5} $
$ \frac{14}{5} $
2$\frac{4}{5}$

	\( \frac{4}{15} \)
	\( \frac{2}{3} \)
	\( \frac{1}{2} \)
	\( \frac{7}{19} \)

	1\(\frac{2}{5}\)
	\(\frac{1}{3}\)
	2\(\frac{4}{5}\)
	1