| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.55 |
| Score | 0% | 71% |
What is the distance in miles of a trip that takes 1 hour at an average speed of 40 miles per hour?
| 40 miles | |
| 450 miles | |
| 160 miles | |
| 120 miles |
Average speed in miles per hour is the number of miles traveled divided by the number of hours:
speed = \( \frac{\text{distance}}{\text{time}} \)Solving for distance:
distance = \( \text{speed} \times \text{time} \)
distance = \( 40mph \times 1h \)
40 miles
If a car travels 100 miles in 4 hours, what is the average speed?
| 20 mph | |
| 25 mph | |
| 60 mph | |
| 75 mph |
Average speed in miles per hour is the number of miles traveled divided by the number of hours:
speed = \( \frac{\text{distance}}{\text{time}} \)A tiger in a zoo has consumed 55 pounds of food in 5 days. If the tiger continues to eat at the same rate, in how many more days will its total food consumtion be 99 pounds?
| 8 | |
| 83 | |
| 53 | |
| 4 |
If the tiger has consumed 55 pounds of food in 5 days that's \( \frac{55}{5} \) = 11 pounds of food per day. The tiger needs to consume 99 - 55 = 44 more pounds of food to reach 99 pounds total. At 11 pounds of food per day that's \( \frac{44}{11} \) = 4 more days.
Damon loaned Christine $1,400 at an annual interest rate of 2%. If no payments are made, what is the total amount owed at the end of the first year?
| $1,414 | |
| $1,442 | |
| $1,470 | |
| $1,428 |
The yearly interest charged on this loan is the annual interest rate multiplied by the amount borrowed:
interest = annual interest rate x loan amount
i = (\( \frac{6}{100} \)) x $1,400
i = 0.02 x $1,400
No payments were made so the total amount due is the original amount + the accumulated interest:
total = $1,400 + $28\({b + c \over a} = {b \over a} + {c \over a}\) defines which of the following?
distributive property for division |
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distributive property for multiplication |
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commutative property for multiplication |
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commutative property for division |
The distributive property for division helps in solving expressions like \({b + c \over a}\). It specifies that the result of dividing a fraction with multiple terms in the numerator and one term in the denominator can be obtained by dividing each term individually and then totaling the results: \({b + c \over a} = {b \over a} + {c \over a}\). For example, \({a^3 + 6a^2 \over a^2} = {a^3 \over a^2} + {6a^2 \over a^2} = a + 6\).