| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.60 |
| Score | 0% | 52% |
A sports card collection contains football, baseball, and basketball cards. If the ratio of football to baseball cards is 3 to 2 and the ratio of baseball to basketball cards is 3 to 1, what is the ratio of football to basketball cards?
| 5:8 | |
| 7:4 | |
| 9:2 | |
| 9:1 |
The ratio of football cards to baseball cards is 3:2 and the ratio of baseball cards to basketball cards is 3:1. To solve this problem, we need the baseball card side of each ratio to be equal so we need to rewrite the ratios in terms of a common number of baseball cards. (Think of this like finding the common denominator when adding fractions.) The ratio of football to baseball cards can also be written as 9:6 and the ratio of baseball cards to basketball cards as 6:2. So, the ratio of football cards to basketball cards is football:baseball, baseball:basketball or 9:6, 6:2 which reduces to 9:2.
This property states taht the order of addition or multiplication does not mater. For example, 2 + 5 and 5 + 2 are equivalent.
commutative |
|
distributive |
|
associative |
|
PEDMAS |
The commutative property states that, when adding or multiplying numbers, the order in which they're added or multiplied does not matter. For example, 3 + 4 and 4 + 3 give the same result, as do 3 x 4 and 4 x 3.
If the ratio of home fans to visiting fans in a crowd is 4:1 and all 39,000 seats in a stadium are filled, how many home fans are in attendance?
| 32,800 | |
| 25,500 | |
| 31,200 | |
| 25,000 |
A ratio of 4:1 means that there are 4 home fans for every one visiting fan. So, of every 5 fans, 4 are home fans and \( \frac{4}{5} \) of every fan in the stadium is a home fan:
39,000 fans x \( \frac{4}{5} \) = \( \frac{156000}{5} \) = 31,200 fans.
Simplify \( \sqrt{50} \)
| 5\( \sqrt{2} \) | |
| 9\( \sqrt{2} \) | |
| 5\( \sqrt{4} \) | |
| 2\( \sqrt{2} \) |
To simplify a radical, factor out the perfect squares:
\( \sqrt{50} \)
\( \sqrt{25 \times 2} \)
\( \sqrt{5^2 \times 2} \)
5\( \sqrt{2} \)
What is \( 4 \)\( \sqrt{27} \) + \( 3 \)\( \sqrt{3} \)
| 15\( \sqrt{3} \) | |
| 12\( \sqrt{81} \) | |
| 12\( \sqrt{3} \) | |
| 12\( \sqrt{9} \) |
To add these radicals together their radicands must be the same:
4\( \sqrt{27} \) + 3\( \sqrt{3} \)
4\( \sqrt{9 \times 3} \) + 3\( \sqrt{3} \)
4\( \sqrt{3^2 \times 3} \) + 3\( \sqrt{3} \)
(4)(3)\( \sqrt{3} \) + 3\( \sqrt{3} \)
12\( \sqrt{3} \) + 3\( \sqrt{3} \)
Now that the radicands are identical, you can add them together:
12\( \sqrt{3} \) + 3\( \sqrt{3} \)