| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.24 |
| Score | 0% | 65% |
Which of these numbers is a factor of 32?
| 1 | |
| 19 | |
| 6 | |
| 35 |
The factors of a number are all positive integers that divide evenly into the number. The factors of 32 are 1, 2, 4, 8, 16, 32.
What is -3c6 x 8c3?
| -24c18 | |
| -24c3 | |
| 5c9 | |
| -24c9 |
To multiply terms with exponents, the base of both exponents must be the same. In this case they are so multiply the coefficients and add the exponents:
-3c6 x 8c3
(-3 x 8)c(6 + 3)
-24c9
Christine scored 90% on her final exam. If each question was worth 4 points and there were 360 possible points on the exam, how many questions did Christine answer correctly?
| 81 | |
| 88 | |
| 90 | |
| 68 |
Christine scored 90% on the test meaning she earned 90% of the possible points on the test. There were 360 possible points on the test so she earned 360 x 0.9 = 324 points. Each question is worth 4 points so she got \( \frac{324}{4} \) = 81 questions right.
What is \( \frac{1}{9} \) x \( \frac{1}{8} \)?
| \(\frac{8}{35}\) | |
| \(\frac{1}{72}\) | |
| \(\frac{1}{18}\) | |
| \(\frac{1}{9}\) |
To multiply fractions, multiply the numerators together and then multiply the denominators together:
\( \frac{1}{9} \) x \( \frac{1}{8} \) = \( \frac{1 x 1}{9 x 8} \) = \( \frac{1}{72} \) = \(\frac{1}{72}\)
Solve 3 + (2 + 5) ÷ 2 x 3 - 32
| \(\frac{1}{4}\) | |
| 1\(\frac{2}{7}\) | |
| 1\(\frac{2}{5}\) | |
| 4\(\frac{1}{2}\) |
Use PEMDAS (Parentheses, Exponents, Multipy/Divide, Add/Subtract):
3 + (2 + 5) ÷ 2 x 3 - 32
P: 3 + (7) ÷ 2 x 3 - 32
E: 3 + 7 ÷ 2 x 3 - 9
MD: 3 + \( \frac{7}{2} \) x 3 - 9
MD: 3 + \( \frac{21}{2} \) - 9
AS: \( \frac{6}{2} \) + \( \frac{21}{2} \) - 9
AS: \( \frac{27}{2} \) - 9
AS: \( \frac{27 - 18}{2} \)
\( \frac{9}{2} \)
4\(\frac{1}{2}\)