ASVAB Arithmetic Reasoning Practice Test 689489 Results

	Your Results	Global Average
Questions	5	5
Correct	0	3.01
Score	0%	60%

Review

Ezra loaned Ezra $1,200 at an annual interest rate of 9%. If no payments are made, what is the interest owed on this loan at the end of the first year?

74% Answer Correctly

	$45
	$84
	$65
	$108

Solution

The yearly interest charged on this loan is the annual interest rate multiplied by the amount borrowed:

interest = annual interest rate x loan amount

i = ($ \frac{6}{100} $) x $1,200
i = 0.09 x $1,200
i = $108

A menswear store is having a sale: "Buy one shirt at full price and get another shirt for 35% off." If Monty buys two shirts, each with a regular price of $34, how much money will he save?

70% Answer Correctly

	$8.50
	$3.40
	$15.30
	$11.90

Solution

By buying two shirts, Monty will save $34 x $ \frac{35}{100} $ = $ \frac{$34 x 35}{100} $ = $ \frac{$1190}{100} $ = $11.90 on the second shirt.

What is the next number in this sequence: 1, 3, 7, 13, 21, __________ ?

68% Answer Correctly

	31
	39
	22
	38

Solution

The equation for this sequence is:

a_n = a_n-1 + 2(n - 1)

where n is the term's order in the sequence, a_n is the value of the term, and a_n-1 is the value of the term before a_n. This makes the next number:

a₆ = a₅ + 2(6 - 1)
a₆ = 21 + 2(5)
a₆ = 31

Solve 2 + (5 + 5) ÷ 4 x 4 - 2²

52% Answer Correctly

	$\frac{6}{7}$
	$\frac{1}{2}$
	8
	$\frac{5}{6}$

Solution

Use PEMDAS (Parentheses, Exponents, Multipy/Divide, Add/Subtract):

2 + (5 + 5) ÷ 4 x 4 - 2²
P: 2 + (10) ÷ 4 x 4 - 2²
E: 2 + 10 ÷ 4 x 4 - 4
MD: 2 + $ \frac{10}{4} $ x 4 - 4
MD: 2 + $ \frac{40}{4} $ - 4
AS: $ \frac{8}{4} $ + $ \frac{40}{4} $ - 4
AS: $ \frac{48}{4} $ - 4
AS: $ \frac{48 - 16}{4} $
$ \frac{32}{4} $
8

What is $ 4 $$ \sqrt{28} $ - $ 2 $$ \sqrt{7} $

38% Answer Correctly

	2$ \sqrt{4} $
	2$ \sqrt{45} $
	6$ \sqrt{7} $
	2$ \sqrt{196} $

Solution

To subtract these radicals together their radicands must be the same:

4$ \sqrt{28} $ - 2$ \sqrt{7} $
4$ \sqrt{4 \times 7} $ - 2$ \sqrt{7} $
4$ \sqrt{2^2 \times 7} $ - 2$ \sqrt{7} $
(4)(2)$ \sqrt{7} $ - 2$ \sqrt{7} $
8$ \sqrt{7} $ - 2$ \sqrt{7} $

Now that the radicands are identical, you can subtract them:

8$ \sqrt{7} $ - 2$ \sqrt{7} $
(8 - 2)$ \sqrt{7} $
6$ \sqrt{7} $

	2\( \sqrt{4} \)
	2\( \sqrt{45} \)
	6\( \sqrt{7} \)
	2\( \sqrt{196} \)

	\(\frac{6}{7}\)
	\(\frac{1}{2}\)
	8
	\(\frac{5}{6}\)