ASVAB Arithmetic Reasoning Practice Test 689629 Results

Your Results Global Average
Questions 5 5
Correct 0 3.24
Score 0% 65%

Review

1

What is \( \sqrt{\frac{49}{64}} \)?

70% Answer Correctly
\(\frac{7}{8}\)
\(\frac{2}{3}\)
\(\frac{4}{9}\)
\(\frac{1}{3}\)

Solution

To take the square root of a fraction, break the fraction into two separate roots then calculate the square root of the numerator and denominator separately:

\( \sqrt{\frac{49}{64}} \)
\( \frac{\sqrt{49}}{\sqrt{64}} \)
\( \frac{\sqrt{7^2}}{\sqrt{8^2}} \)
\(\frac{7}{8}\)


2

Diane scored 90% on her final exam. If each question was worth 4 points and there were 360 possible points on the exam, how many questions did Diane answer correctly?

57% Answer Correctly
84
66
72
81

Solution

Diane scored 90% on the test meaning she earned 90% of the possible points on the test. There were 360 possible points on the test so she earned 360 x 0.9 = 324 points. Each question is worth 4 points so she got \( \frac{324}{4} \) = 81 questions right.


3

What is the distance in miles of a trip that takes 4 hours at an average speed of 60 miles per hour?

87% Answer Correctly
315 miles
240 miles
45 miles
245 miles

Solution

Average speed in miles per hour is the number of miles traveled divided by the number of hours:

speed = \( \frac{\text{distance}}{\text{time}} \)

Solving for distance:

distance = \( \text{speed} \times \text{time} \)
distance = \( 60mph \times 4h \)
240 miles


4

53% Answer Correctly
7.2
3.0
1
3.5

Solution


1


5

\({b + c \over a} = {b \over a} + {c \over a}\) defines which of the following?

56% Answer Correctly

distributive property for division

commutative property for multiplication

commutative property for division

distributive property for multiplication


Solution

The distributive property for division helps in solving expressions like \({b + c \over a}\). It specifies that the result of dividing a fraction with multiple terms in the numerator and one term in the denominator can be obtained by dividing each term individually and then totaling the results: \({b + c \over a} = {b \over a} + {c \over a}\). For example, \({a^3 + 6a^2 \over a^2} = {a^3 \over a^2} + {6a^2 \over a^2} = a + 6\).