| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.97 |
| Score | 0% | 59% |
If the ratio of home fans to visiting fans in a crowd is 3:1 and all 33,000 seats in a stadium are filled, how many home fans are in attendance?
| 35,000 | |
| 24,750 | |
| 32,000 | |
| 32,800 |
A ratio of 3:1 means that there are 3 home fans for every one visiting fan. So, of every 4 fans, 3 are home fans and \( \frac{3}{4} \) of every fan in the stadium is a home fan:
33,000 fans x \( \frac{3}{4} \) = \( \frac{99000}{4} \) = 24,750 fans.
What is 8\( \sqrt{3} \) x 4\( \sqrt{6} \)?
| 96\( \sqrt{2} \) | |
| 12\( \sqrt{18} \) | |
| 12\( \sqrt{6} \) | |
| 32\( \sqrt{9} \) |
To multiply terms with radicals, multiply the coefficients and radicands separately:
8\( \sqrt{3} \) x 4\( \sqrt{6} \)
(8 x 4)\( \sqrt{3 \times 6} \)
32\( \sqrt{18} \)
Now we need to simplify the radical:
32\( \sqrt{18} \)
32\( \sqrt{2 \times 9} \)
32\( \sqrt{2 \times 3^2} \)
(32)(3)\( \sqrt{2} \)
96\( \sqrt{2} \)
Simplify \( \frac{20}{60} \).
| \( \frac{6}{19} \) | |
| \( \frac{1}{3} \) | |
| \( \frac{10}{13} \) | |
| \( \frac{3}{4} \) |
To simplify this fraction, first find the greatest common factor between them. The factors of 20 are [1, 2, 4, 5, 10, 20] and the factors of 60 are [1, 2, 3, 4, 5, 6, 10, 12, 15, 20, 30, 60]. They share 6 factors [1, 2, 4, 5, 10, 20] making 20 their greatest common factor (GCF).
Next, divide both numerator and denominator by the GCF:
\( \frac{20}{60} \) = \( \frac{\frac{20}{20}}{\frac{60}{20}} \) = \( \frac{1}{3} \)
If \(\left|a\right| = 7\), which of the following best describes a?
a = 7 |
|
a = 7 or a = -7 |
|
a = -7 |
|
none of these is correct |
The absolute value is the positive magnitude of a particular number or variable and is indicated by two vertical lines: \(\left|-5\right| = 5\). In the case of a variable absolute value (\(\left|a\right| = 5\)) the value of a can be either positive or negative (a = -5 or a = 5).
What is \( \frac{6}{5} \) + \( \frac{2}{9} \)?
| 2 \( \frac{6}{45} \) | |
| 1\(\frac{19}{45}\) | |
| 1 \( \frac{4}{10} \) | |
| 2 \( \frac{2}{45} \) |
To add these fractions, first find the lowest common multiple of their denominators. The first few multiples of 5 are [5, 10, 15, 20, 25, 30, 35, 40, 45, 50] and the first few multiples of 9 are [9, 18, 27, 36, 45, 54, 63, 72, 81, 90]. The first few multiples they share are [45, 90] making 45 the smallest multiple 5 and 9 share.
Next, convert the fractions so each denominator equals the lowest common multiple:
\( \frac{6 x 9}{5 x 9} \) + \( \frac{2 x 5}{9 x 5} \)
\( \frac{54}{45} \) + \( \frac{10}{45} \)
Now, because the fractions share a common denominator, you can add them:
\( \frac{54 + 10}{45} \) = \( \frac{64}{45} \) = 1\(\frac{19}{45}\)