| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.17 |
| Score | 0% | 63% |
What is \( \frac{1}{6} \) x \( \frac{2}{5} \)?
| \(\frac{1}{10}\) | |
| \(\frac{1}{15}\) | |
| \(\frac{1}{3}\) | |
| \(\frac{2}{35}\) |
To multiply fractions, multiply the numerators together and then multiply the denominators together:
\( \frac{1}{6} \) x \( \frac{2}{5} \) = \( \frac{1 x 2}{6 x 5} \) = \( \frac{2}{30} \) = \(\frac{1}{15}\)
A tiger in a zoo has consumed 98 pounds of food in 7 days. If the tiger continues to eat at the same rate, in how many more days will its total food consumtion be 168 pounds?
| 59 | |
| 7 | |
| 5 | |
| 3 |
If the tiger has consumed 98 pounds of food in 7 days that's \( \frac{98}{7} \) = 14 pounds of food per day. The tiger needs to consume 168 - 98 = 70 more pounds of food to reach 168 pounds total. At 14 pounds of food per day that's \( \frac{70}{14} \) = 5 more days.
Damon loaned Monty $600 at an annual interest rate of 2%. If no payments are made, what is the interest owed on this loan at the end of the first year?
| $90 | |
| $24 | |
| $91 | |
| $12 |
The yearly interest charged on this loan is the annual interest rate multiplied by the amount borrowed:
interest = annual interest rate x loan amount
i = (\( \frac{6}{100} \)) x $600
i = 0.02 x $600
i = $12
What is the least common multiple of 3 and 7?
| 21 | |
| 15 | |
| 13 | |
| 20 |
The first few multiples of 3 are [3, 6, 9, 12, 15, 18, 21, 24, 27, 30] and the first few multiples of 7 are [7, 14, 21, 28, 35, 42, 49, 56, 63, 70]. The first few multiples they share are [21, 42, 63, 84] making 21 the smallest multiple 3 and 7 have in common.
Cooks are needed to prepare for a large party. Each cook can bake either 2 large cakes or 14 small cakes per hour. The kitchen is available for 2 hours and 21 large cakes and 290 small cakes need to be baked.
How many cooks are required to bake the required number of cakes during the time the kitchen is available?
| 10 | |
| 17 | |
| 7 | |
| 6 |
If a single cook can bake 2 large cakes per hour and the kitchen is available for 2 hours, a single cook can bake 2 x 2 = 4 large cakes during that time. 21 large cakes are needed for the party so \( \frac{21}{4} \) = 5\(\frac{1}{4}\) cooks are needed to bake the required number of large cakes.
If a single cook can bake 14 small cakes per hour and the kitchen is available for 2 hours, a single cook can bake 14 x 2 = 28 small cakes during that time. 290 small cakes are needed for the party so \( \frac{290}{28} \) = 10\(\frac{5}{14}\) cooks are needed to bake the required number of small cakes.
Because you can't employ a fractional cook, round the number of cooks needed for each type of cake up to the next whole number resulting in 6 + 11 = 17 cooks.