| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.55 |
| Score | 0% | 71% |
If a car travels 315 miles in 9 hours, what is the average speed?
| 15 mph | |
| 35 mph | |
| 55 mph | |
| 40 mph |
Average speed in miles per hour is the number of miles traveled divided by the number of hours:
speed = \( \frac{\text{distance}}{\text{time}} \)What is \( \frac{14\sqrt{63}}{2\sqrt{9}} \)?
| 7 \( \sqrt{\frac{1}{7}} \) | |
| \(\frac{1}{7}\) \( \sqrt{7} \) | |
| \(\frac{1}{7}\) \( \sqrt{\frac{1}{7}} \) | |
| 7 \( \sqrt{7} \) |
To divide terms with radicals, divide the coefficients and radicands separately:
\( \frac{14\sqrt{63}}{2\sqrt{9}} \)
\( \frac{14}{2} \) \( \sqrt{\frac{63}{9}} \)
7 \( \sqrt{7} \)
a(b + c) = ab + ac defines which of the following?
distributive property for division |
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commutative property for division |
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distributive property for multiplication |
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commutative property for multiplication |
The distributive property for multiplication helps in solving expressions like a(b + c). It specifies that the result of multiplying one number by the sum or difference of two numbers can be obtained by multiplying each number individually and then totaling the results: a(b + c) = ab + ac. For example, 4(10-5) = (4 x 10) - (4 x 5) = 40 - 20 = 20.
Convert y-2 to remove the negative exponent.
| \( \frac{1}{y^2} \) | |
| \( \frac{-1}{-2y^{2}} \) | |
| \( \frac{-1}{y^{-2}} \) | |
| \( \frac{-2}{-y} \) |
To convert a negative exponent to a positive exponent, calculate the positive exponent then take the reciprocal.
\({b + c \over a} = {b \over a} + {c \over a}\) defines which of the following?
commutative property for division |
|
distributive property for multiplication |
|
distributive property for division |
|
commutative property for multiplication |
The distributive property for division helps in solving expressions like \({b + c \over a}\). It specifies that the result of dividing a fraction with multiple terms in the numerator and one term in the denominator can be obtained by dividing each term individually and then totaling the results: \({b + c \over a} = {b \over a} + {c \over a}\). For example, \({a^3 + 6a^2 \over a^2} = {a^3 \over a^2} + {6a^2 \over a^2} = a + 6\).