| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.07 |
| Score | 0% | 61% |
Monty loaned Jennifer $1,000 at an annual interest rate of 3%. If no payments are made, what is the total amount owed at the end of the first year?
| $1,040 | |
| $1,030 | |
| $1,050 | |
| $1,080 |
The yearly interest charged on this loan is the annual interest rate multiplied by the amount borrowed:
interest = annual interest rate x loan amount
i = (\( \frac{6}{100} \)) x $1,000
i = 0.03 x $1,000
No payments were made so the total amount due is the original amount + the accumulated interest:
total = $1,000 + $30
| 1.4 | |
| 8.0 | |
| 1 | |
| 5.4 |
1
If a rectangle is twice as long as it is wide and has a perimeter of 12 meters, what is the area of the rectangle?
| 98 m2 | |
| 72 m2 | |
| 8 m2 | |
| 50 m2 |
The area of a rectangle is width (w) x height (h). In this problem we know that the rectangle is twice as long as it is wide so h = 2w. The perimeter of a rectangle is 2w + 2h and we know that the perimeter of this rectangle is 12 meters so the equation becomes: 2w + 2h = 12.
Putting these two equations together and solving for width (w):
2w + 2h = 12
w + h = \( \frac{12}{2} \)
w + h = 6
w = 6 - h
From the question we know that h = 2w so substituting 2w for h gives us:
w = 6 - 2w
3w = 6
w = \( \frac{6}{3} \)
w = 2
Since h = 2w that makes h = (2 x 2) = 4 and the area = h x w = 2 x 4 = 8 m2
What is \( \frac{3}{6} \) x \( \frac{3}{6} \)?
| \(\frac{1}{10}\) | |
| \(\frac{16}{35}\) | |
| \(\frac{1}{4}\) | |
| \(\frac{2}{7}\) |
To multiply fractions, multiply the numerators together and then multiply the denominators together:
\( \frac{3}{6} \) x \( \frac{3}{6} \) = \( \frac{3 x 3}{6 x 6} \) = \( \frac{9}{36} \) = \(\frac{1}{4}\)
If \( \left|c - 6\right| \) - 4 = -5, which of these is a possible value for c?
| 4 | |
| -15 | |
| 7 | |
| 3 |
First, solve for \( \left|c - 6\right| \):
\( \left|c - 6\right| \) - 4 = -5
\( \left|c - 6\right| \) = -5 + 4
\( \left|c - 6\right| \) = -1
The value inside the absolute value brackets can be either positive or negative so (c - 6) must equal - 1 or --1 for \( \left|c - 6\right| \) to equal -1:
| c - 6 = -1 c = -1 + 6 c = 5 | c - 6 = 1 c = 1 + 6 c = 7 |
So, c = 7 or c = 5.