| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 2.79 |
| Score | 0% | 56% |
What is the greatest common factor of 24 and 24?
| 18 | |
| 11 | |
| 24 | |
| 3 |
The factors of 24 are [1, 2, 3, 4, 6, 8, 12, 24] and the factors of 24 are [1, 2, 3, 4, 6, 8, 12, 24]. They share 8 factors [1, 2, 3, 4, 6, 8, 12, 24] making 24 the greatest factor 24 and 24 have in common.
What is \( 5 \)\( \sqrt{125} \) + \( 5 \)\( \sqrt{5} \)
| 10\( \sqrt{5} \) | |
| 30\( \sqrt{5} \) | |
| 10\( \sqrt{625} \) | |
| 25\( \sqrt{125} \) |
To add these radicals together their radicands must be the same:
5\( \sqrt{125} \) + 5\( \sqrt{5} \)
5\( \sqrt{25 \times 5} \) + 5\( \sqrt{5} \)
5\( \sqrt{5^2 \times 5} \) + 5\( \sqrt{5} \)
(5)(5)\( \sqrt{5} \) + 5\( \sqrt{5} \)
25\( \sqrt{5} \) + 5\( \sqrt{5} \)
Now that the radicands are identical, you can add them together:
25\( \sqrt{5} \) + 5\( \sqrt{5} \)If the ratio of home fans to visiting fans in a crowd is 2:1 and all 31,000 seats in a stadium are filled, how many home fans are in attendance?
| 37,500 | |
| 20,667 | |
| 34,400 | |
| 26,250 |
A ratio of 2:1 means that there are 2 home fans for every one visiting fan. So, of every 3 fans, 2 are home fans and \( \frac{2}{3} \) of every fan in the stadium is a home fan:
31,000 fans x \( \frac{2}{3} \) = \( \frac{62000}{3} \) = 20,667 fans.
Solve 5 + (5 + 5) ÷ 4 x 4 - 52
| \(\frac{5}{6}\) | |
| -10 | |
| 1\(\frac{1}{2}\) | |
| \(\frac{1}{2}\) |
Use PEMDAS (Parentheses, Exponents, Multipy/Divide, Add/Subtract):
5 + (5 + 5) ÷ 4 x 4 - 52
P: 5 + (10) ÷ 4 x 4 - 52
E: 5 + 10 ÷ 4 x 4 - 25
MD: 5 + \( \frac{10}{4} \) x 4 - 25
MD: 5 + \( \frac{40}{4} \) - 25
AS: \( \frac{20}{4} \) + \( \frac{40}{4} \) - 25
AS: \( \frac{60}{4} \) - 25
AS: \( \frac{60 - 100}{4} \)
\( \frac{-40}{4} \)
-10
If \( \left|y + 8\right| \) + 1 = -1, which of these is a possible value for y?
| 15 | |
| -6 | |
| -12 | |
| -8 |
First, solve for \( \left|y + 8\right| \):
\( \left|y + 8\right| \) + 1 = -1
\( \left|y + 8\right| \) = -1 - 1
\( \left|y + 8\right| \) = -2
The value inside the absolute value brackets can be either positive or negative so (y + 8) must equal - 2 or --2 for \( \left|y + 8\right| \) to equal -2:
| y + 8 = -2 y = -2 - 8 y = -10 | y + 8 = 2 y = 2 - 8 y = -6 |
So, y = -6 or y = -10.