ASVAB Arithmetic Reasoning Practice Test 697494 Results

Your Results Global Average
Questions 5 5
Correct 0 2.84
Score 0% 57%

Review

1

Which of the following is not a prime number?

65% Answer Correctly

7

5

2

9


Solution

A prime number is an integer greater than 1 that has no factors other than 1 and itself. Examples of prime numbers include 2, 3, 5, 7, and 11.


2

How many 1\(\frac{1}{2}\) gallon cans worth of fuel would you need to pour into an empty 9 gallon tank to fill it exactly halfway?

52% Answer Correctly
6
7
3
9

Solution

To fill a 9 gallon tank exactly halfway you'll need 4\(\frac{1}{2}\) gallons of fuel. Each fuel can holds 1\(\frac{1}{2}\) gallons so:

cans = \( \frac{4\frac{1}{2} \text{ gallons}}{1\frac{1}{2} \text{ gallons}} \) = 3


3

This property states taht the order of addition or multiplication does not mater. For example, 2 + 5 and 5 + 2 are equivalent.

60% Answer Correctly

associative

commutative

distributive

PEDMAS


Solution

The commutative property states that, when adding or multiplying numbers, the order in which they're added or multiplied does not matter. For example, 3 + 4 and 4 + 3 give the same result, as do 3 x 4 and 4 x 3.


4

If a rectangle is twice as long as it is wide and has a perimeter of 12 meters, what is the area of the rectangle?

47% Answer Correctly
50 m2
32 m2
8 m2
98 m2

Solution

The area of a rectangle is width (w) x height (h). In this problem we know that the rectangle is twice as long as it is wide so h = 2w. The perimeter of a rectangle is 2w + 2h and we know that the perimeter of this rectangle is 12 meters so the equation becomes: 2w + 2h = 12.

Putting these two equations together and solving for width (w):

2w + 2h = 12
w + h = \( \frac{12}{2} \)
w + h = 6
w = 6 - h

From the question we know that h = 2w so substituting 2w for h gives us:

w = 6 - 2w
3w = 6
w = \( \frac{6}{3} \)
w = 2

Since h = 2w that makes h = (2 x 2) = 4 and the area = h x w = 2 x 4 = 8 m2


5

What is \( \frac{3a^9}{8a^4} \)?

60% Answer Correctly
\(\frac{3}{8}\)a2\(\frac{1}{4}\)
2\(\frac{2}{3}\)a5
2\(\frac{2}{3}\)a-5
\(\frac{3}{8}\)a5

Solution

To divide terms with exponents, the base of both exponents must be the same. In this case they are so divide the coefficients and subtract the exponents:

\( \frac{3a^9}{8a^4} \)
\( \frac{3}{8} \) a(9 - 4)
\(\frac{3}{8}\)a5