ASVAB Arithmetic Reasoning Practice Test 697720 Results

Your Results Global Average
Questions 5 5
Correct 0 3.28
Score 0% 66%

Review

1

What is \( \frac{10\sqrt{49}}{5\sqrt{7}} \)?

71% Answer Correctly
2 \( \sqrt{7} \)
\(\frac{1}{2}\) \( \sqrt{7} \)
\(\frac{1}{7}\) \( \sqrt{2} \)
\(\frac{1}{2}\) \( \sqrt{\frac{1}{7}} \)

Solution

To divide terms with radicals, divide the coefficients and radicands separately:

\( \frac{10\sqrt{49}}{5\sqrt{7}} \)
\( \frac{10}{5} \) \( \sqrt{\frac{49}{7}} \)
2 \( \sqrt{7} \)


2

Convert z-4 to remove the negative exponent.

68% Answer Correctly
\( \frac{-1}{-4z^{4}} \)
\( \frac{1}{z^4} \)
\( \frac{-1}{-4z} \)
\( \frac{4}{z} \)

Solution

To convert a negative exponent to a positive exponent, calculate the positive exponent then take the reciprocal.


3

Monty loaned Betty $1,300 at an annual interest rate of 9%. If no payments are made, what is the total amount owed at the end of the first year?

71% Answer Correctly
$1,417
$1,339
$1,365
$1,404

Solution

The yearly interest charged on this loan is the annual interest rate multiplied by the amount borrowed:

interest = annual interest rate x loan amount

i = (\( \frac{6}{100} \)) x $1,300
i = 0.09 x $1,300

No payments were made so the total amount due is the original amount + the accumulated interest:

total = $1,300 + $117
total = $1,417


4

How many 1 gallon cans worth of fuel would you need to pour into an empty 4 gallon tank to fill it exactly halfway?

52% Answer Correctly
8
4
9
2

Solution

To fill a 4 gallon tank exactly halfway you'll need 2 gallons of fuel. Each fuel can holds 1 gallons so:

cans = \( \frac{2 \text{ gallons}}{1 \text{ gallons}} \) = 2


5

If \(\left|a\right| = 7\), which of the following best describes a?

67% Answer Correctly

none of these is correct

a = -7

a = 7 or a = -7

a = 7


Solution

The absolute value is the positive magnitude of a particular number or variable and is indicated by two vertical lines: \(\left|-5\right| = 5\). In the case of a variable absolute value (\(\left|a\right| = 5\)) the value of a can be either positive or negative (a = -5 or a = 5).