| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.31 |
| Score | 0% | 66% |
A menswear store is having a sale: "Buy one shirt at full price and get another shirt for 30% off." If Damon buys two shirts, each with a regular price of $40, how much money will he save?
| $12.00 | |
| $16.00 | |
| $18.00 | |
| $20.00 |
By buying two shirts, Damon will save $40 x \( \frac{30}{100} \) = \( \frac{$40 x 30}{100} \) = \( \frac{$1200}{100} \) = $12.00 on the second shirt.
Roger loaned Jennifer $500 at an annual interest rate of 6%. If no payments are made, what is the total amount owed at the end of the first year?
| $530 | |
| $505 | |
| $525 | |
| $540 |
The yearly interest charged on this loan is the annual interest rate multiplied by the amount borrowed:
interest = annual interest rate x loan amount
i = (\( \frac{6}{100} \)) x $500
i = 0.06 x $500
No payments were made so the total amount due is the original amount + the accumulated interest:
total = $500 + $30On average, the center for a basketball team hits 30% of his shots while a guard on the same team hits 45% of his shots. If the guard takes 10 shots during a game, how many shots will the center have to take to score as many points as the guard assuming each shot is worth the same number of points?
| 7 | |
| 13 | |
| 15 | |
| 8 |
guard shots made = shots taken x \( \frac{\text{% made}}{100} \) = 10 x \( \frac{45}{100} \) = \( \frac{45 x 10}{100} \) = \( \frac{450}{100} \) = 4 shots
The center makes 30% of his shots so he'll have to take:
shots made = shots taken x \( \frac{\text{% made}}{100} \)
shots taken = \( \frac{\text{shots taken}}{\frac{\text{% made}}{100}} \)
to make as many shots as the guard. Plugging in values for the center gives us:
center shots taken = \( \frac{4}{\frac{30}{100}} \) = 4 x \( \frac{100}{30} \) = \( \frac{4 x 100}{30} \) = \( \frac{400}{30} \) = 13 shots
to make the same number of shots as the guard and thus score the same number of points.
What is (a5)2?
| a-3 | |
| a3 | |
| 2a5 | |
| a10 |
To raise a term with an exponent to another exponent, retain the base and multiply the exponents:
(a5)2Solve for \( \frac{4!}{2!} \)
| \( \frac{1}{4} \) | |
| 12 | |
| 5 | |
| 8 |
A factorial is the product of an integer and all the positive integers below it. To solve a fraction featuring factorials, expand the factorials and cancel out like numbers:
\( \frac{4!}{2!} \)
\( \frac{4 \times 3 \times 2 \times 1}{2 \times 1} \)
\( \frac{4 \times 3}{1} \)
\( 4 \times 3 \)
12