ASVAB Arithmetic Reasoning Practice Test 699363 Results

Your Results Global Average
Questions 5 5
Correct 0 3.33
Score 0% 67%

Review

1

What is \( \frac{3}{6} \) ÷ \( \frac{2}{7} \)?

68% Answer Correctly
1\(\frac{3}{4}\)
3\(\frac{1}{2}\)
\(\frac{1}{16}\)
10\(\frac{1}{2}\)

Solution

To divide fractions, invert the second fraction and then multiply:

\( \frac{3}{6} \) ÷ \( \frac{2}{7} \) = \( \frac{3}{6} \) x \( \frac{7}{2} \)

To multiply fractions, multiply the numerators together and then multiply the denominators together:

\( \frac{3}{6} \) x \( \frac{7}{2} \) = \( \frac{3 x 7}{6 x 2} \) = \( \frac{21}{12} \) = 1\(\frac{3}{4}\)


2

What is \( \frac{2}{6} \) - \( \frac{7}{10} \)?

61% Answer Correctly
\( \frac{1}{30} \)
-\(\frac{11}{30}\)
1 \( \frac{2}{30} \)
1 \( \frac{9}{30} \)

Solution

To subtract these fractions, first find the lowest common multiple of their denominators. The first few multiples of 6 are [6, 12, 18, 24, 30, 36, 42, 48, 54, 60] and the first few multiples of 10 are [10, 20, 30, 40, 50, 60, 70, 80, 90]. The first few multiples they share are [30, 60, 90] making 30 the smallest multiple 6 and 10 share.

Next, convert the fractions so each denominator equals the lowest common multiple:

\( \frac{2 x 5}{6 x 5} \) - \( \frac{7 x 3}{10 x 3} \)

\( \frac{10}{30} \) - \( \frac{21}{30} \)

Now, because the fractions share a common denominator, you can subtract them:

\( \frac{10 - 21}{30} \) = \( \frac{-11}{30} \) = -\(\frac{11}{30}\)


3

What is -5a2 x 3a3?

75% Answer Correctly
-2a3
-15a-1
-15a5
-15a2

Solution

To multiply terms with exponents, the base of both exponents must be the same. In this case they are so multiply the coefficients and add the exponents:

-5a2 x 3a3
(-5 x 3)a(2 + 3)
-15a5


4

Which of these numbers is a factor of 32?

69% Answer Correctly
23
6
12
4

Solution

The factors of a number are all positive integers that divide evenly into the number. The factors of 32 are 1, 2, 4, 8, 16, 32.


5

What is \( \frac{9a^9}{5a^3} \)?

60% Answer Correctly
\(\frac{5}{9}\)a12
1\(\frac{4}{5}\)a-6
\(\frac{5}{9}\)a-6
1\(\frac{4}{5}\)a6

Solution

To divide terms with exponents, the base of both exponents must be the same. In this case they are so divide the coefficients and subtract the exponents:

\( \frac{9a^9}{5a^3} \)
\( \frac{9}{5} \) a(9 - 3)
1\(\frac{4}{5}\)a6