| Your Results | Global Average | |
|---|---|---|
| Questions | 5 | 5 |
| Correct | 0 | 3.33 |
| Score | 0% | 67% |
What is \( \frac{3}{6} \) ÷ \( \frac{2}{7} \)?
| 1\(\frac{3}{4}\) | |
| 3\(\frac{1}{2}\) | |
| \(\frac{1}{16}\) | |
| 10\(\frac{1}{2}\) |
To divide fractions, invert the second fraction and then multiply:
\( \frac{3}{6} \) ÷ \( \frac{2}{7} \) = \( \frac{3}{6} \) x \( \frac{7}{2} \)
To multiply fractions, multiply the numerators together and then multiply the denominators together:
\( \frac{3}{6} \) x \( \frac{7}{2} \) = \( \frac{3 x 7}{6 x 2} \) = \( \frac{21}{12} \) = 1\(\frac{3}{4}\)
What is \( \frac{2}{6} \) - \( \frac{7}{10} \)?
| \( \frac{1}{30} \) | |
| -\(\frac{11}{30}\) | |
| 1 \( \frac{2}{30} \) | |
| 1 \( \frac{9}{30} \) |
To subtract these fractions, first find the lowest common multiple of their denominators. The first few multiples of 6 are [6, 12, 18, 24, 30, 36, 42, 48, 54, 60] and the first few multiples of 10 are [10, 20, 30, 40, 50, 60, 70, 80, 90]. The first few multiples they share are [30, 60, 90] making 30 the smallest multiple 6 and 10 share.
Next, convert the fractions so each denominator equals the lowest common multiple:
\( \frac{2 x 5}{6 x 5} \) - \( \frac{7 x 3}{10 x 3} \)
\( \frac{10}{30} \) - \( \frac{21}{30} \)
Now, because the fractions share a common denominator, you can subtract them:
\( \frac{10 - 21}{30} \) = \( \frac{-11}{30} \) = -\(\frac{11}{30}\)
What is -5a2 x 3a3?
| -2a3 | |
| -15a-1 | |
| -15a5 | |
| -15a2 |
To multiply terms with exponents, the base of both exponents must be the same. In this case they are so multiply the coefficients and add the exponents:
-5a2 x 3a3
(-5 x 3)a(2 + 3)
-15a5
Which of these numbers is a factor of 32?
| 23 | |
| 6 | |
| 12 | |
| 4 |
The factors of a number are all positive integers that divide evenly into the number. The factors of 32 are 1, 2, 4, 8, 16, 32.
What is \( \frac{9a^9}{5a^3} \)?
| \(\frac{5}{9}\)a12 | |
| 1\(\frac{4}{5}\)a-6 | |
| \(\frac{5}{9}\)a-6 | |
| 1\(\frac{4}{5}\)a6 |
To divide terms with exponents, the base of both exponents must be the same. In this case they are so divide the coefficients and subtract the exponents:
\( \frac{9a^9}{5a^3} \)
\( \frac{9}{5} \) a(9 - 3)
1\(\frac{4}{5}\)a6