guard shots made = shots taken x \( \frac{\text{% made}}{100} \) = 25 x \( \frac{60}{100} \) = \( \frac{60 x 25}{100} \) = \( \frac{1500}{100} \) = 15 shots

The center makes 45% of his shots so he'll have to take:

shots made = shots taken x \( \frac{\text{% made}}{100} \)
shots taken = \( \frac{\text{shots taken}}{\frac{\text{% made}}{100}} \)

to make as many shots as the guard. Plugging in values for the center gives us:

center shots taken = \( \frac{15}{\frac{45}{100}} \) = 15 x \( \frac{100}{45} \) = \( \frac{15 x 100}{45} \) = \( \frac{1500}{45} \) = 33 shots

to make the same number of shots as the guard and thus score the same number of points.

The least common multiple (LCM) is the smallest positive integer that is a multiple of two or more integers.

To add these radicals together their radicands must be the same:

9\( \sqrt{175} \) + 7\( \sqrt{7} \)
9\( \sqrt{25 \times 7} \) + 7\( \sqrt{7} \)
9\( \sqrt{5^2 \times 7} \) + 7\( \sqrt{7} \)
(9)(5)\( \sqrt{7} \) + 7\( \sqrt{7} \)
45\( \sqrt{7} \) + 7\( \sqrt{7} \)

Now that the radicands are identical, you can add them together:

To find the average of these 4 numbers add them together then divide by 4:

\( \frac{8 + 4 + 8 + 4}{4} \) = \( \frac{24}{4} \) = 6

The equation for this sequence is:

a_n = a_n-1 + 2(n - 1)

where n is the term's order in the sequence, a_n is the value of the term, and a_n-1 is the value of the term before a_n. This makes the next number:

a₆ = a₅ + 2(6 - 1)
a₆ = 21 + 2(5)
a₆ = 31